if the diameter of a circle is 15, its radius is half that or 7.5.
![\bf \textit{area of a circle}\\\\ A=\pi r^2~~ \begin{cases} r=radius\\[-0.5em] \hrulefill\\ r=7.5 \end{cases} A=\pi (7.5)^2\implies A=56.25\pi \implies \stackrel{\pi =3.14}{A=176.625}](https://tex.z-dn.net/?f=%5Cbf%20%5Ctextit%7Barea%20of%20a%20circle%7D%5C%5C%5C%5C%20A%3D%5Cpi%20r%5E2~~%20%5Cbegin%7Bcases%7D%20r%3Dradius%5C%5C%5B-0.5em%5D%20%5Chrulefill%5C%5C%20r%3D7.5%20%5Cend%7Bcases%7D%20A%3D%5Cpi%20%287.5%29%5E2%5Cimplies%20A%3D56.25%5Cpi%20%5Cimplies%20%5Cstackrel%7B%5Cpi%20%3D3.14%7D%7BA%3D176.625%7D%20)
Answer:
The answer is 20.9
Step-by-step explanation:
Answer:
vkdjdduruyeyetjfdywreytdjgkjfkjgkhkhv;
Step-by-step explanation:
Both exponential i.e 5 ^x
A is true, surprisingly.
B cannot be true, it alternates.(rule of indices negatives by positive exponent = positive, negative by negative , but -5 x -5 x -5 = + 5)
I'm only imaginging, but C must be right, since it increases exponentially, as opposed to D which only increases quadratically.
Answer:
The center is (-4,-6) and the radius is 8
Step-by-step explanation:
(x+4)²+(y+6)²=64
The equation of a circle can be written in the form
(x-h)²+(y-k)²=r^2
Where (h,k) is the center and r is the radius
Rewriting the equation
(x - -4)²+(y- -6)²=8^2
The center is (-4,-6) and the radius is 8
