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Mumz [18]
3 years ago
7

Please help, limited on time!!

Mathematics
2 answers:
Naily [24]3 years ago
8 0

Answer:

D. 5/13

Step-by-step explanation:

Cosin is adjacent/hypotenuse so, the adjacent would be 5 and the hypotenuse is 13 since it is the longest side. This is viewed from angle B.

KATRIN_1 [288]3 years ago
8 0

Answer:

5/13 (answer D)

Step-by-step explanation:

cos beta = adjacent side / hypotenuse = 5 / 13 (answer D)

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Solve the following equation for x, in terms of a and b <br><br> ax= 15+bx
ZanzabumX [31]
Ax=15+bx
ax-bx=15
x(a-b)=15
x=15/(a-b)

4 0
3 years ago
Chuck and Blaire decided to share a 10
klemol [59]

Answer:

A. 7 1/6

Step-by-step explanation:

10 3/4 * 2/3=

43/4 * 2/3= 86/12

86/12 = 7 2/12 = 7 1/6

3 0
2 years ago
PLEASE HELP ASAP…. THIS TEST IS MOST OF MY GRADE
Lemur [1.5K]

Answer:

The answer is D

Step-by-step explanation:

This is so because the opposite of a positive number is that number but negative. Hope this helps!

7 0
2 years ago
Read 2 more answers
What are the vertical and horizontal asymptotes for the function f(x)=3^2/x^-4
Zarrin [17]

The vertical asymptotes x = - 2, 2 and Horizontal asymptotes y = 3

Option A is the correct answer.

<h3>What are Function?</h3>

Function are mathematical statement which links an independent variable to dependent variable.

It always comes with a defined domain and range.

The equation mentioned is incorrect in the question w.r.t. to the solutions mentioned, The right equation is

\rm f(x) = \dfrac{3 x^2}{x^{2}-4}

This function can also be written as

\rm f(x) = \dfrac{3 x^2}{x^{2}-2^2}\\\\\rm f(x) = \dfrac{3 x^2}{(x+2)(x-2)}

Vertical asymptotes are defined when the denominator of a rational function tends to zero.

To find the equation/s let the denominator equal zero.

Denominator tends to zero for x = -2 and x = +2

Horizontal Asymptote is when the function f(x) is tending to zero.

for x = +∞ and x = - ∞

Let the rational function f(x)= \dfrac{mx^a}{nx^b}  where  and a and b are degree of numerator and denominator.

If a < b , then the y axis y = 0 is a horizontal asymptote.

If b = a then horizontal asymptote is the line y = p/q

Here the value is b = 2 and a = 2

Since b = a the horizontal asymptote is the line

y = m/n  where m = 3 and n = 1

Therefore y = 3

So , vertical asymptotes x = - 2, 2

Horizontal asymptotes y = 3

Option A is the correct answer.

To know more about Function

brainly.com/question/12431044

#SPJ1

8 0
2 years ago
Write the point-slope form of the equation of the line through the given point with the given
UNO [17]

Answer:

The point-slope form of the equation is:

  • y-\left(-5\right)=-3\left(x-3\right)

Step-by-step explanation:

Given

  • point (3, -5)
  • slope = -3

We know the point-slope form of the line equation is

y-y_1=m\left(x-x_1\right)

where m is the slope

substituting the values m = -3 and the point (3, -5)

y-y_1=m\left(x-x_1\right)

y-\left(-5\right)=-3\left(x-3\right)

Thus, the point-slope form of the equation is:

  • y-\left(-5\right)=-3\left(x-3\right)
6 0
3 years ago
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