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Artyom0805 [142]
3 years ago
6

Ahaha please help !!!!

Mathematics
2 answers:
Ivahew [28]3 years ago
8 0

Answer:

The answer is A because you have to look at the shape of the plot

Step-by-step explanation:

Anastasy [175]3 years ago
5 0
A took test and the person above is right
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Samantha answered 90% of the questions on her math test and 80 % of the questions on her history test correctly. If each test ha
uranmaximum [27]

Answer:

Samantha got 85 questions right.

Step-by-step explanation:

90% of 50 is 45.

80% of 50 is 40.

40 + 45 = 85

:)

4 0
3 years ago
Read 2 more answers
Plz help its so confusing
aleksklad [387]

Answer:

20, 4

Step-by-step explanation:

Let's assume total number of students registered is n

Last week n/4 people are absent

so people present are n - n/4 = <u>3n/4</u>

Today after return of Jen  1/5 n are absent

so people present are n - n/5 = 4n/5

which is also equal to last week present people + 1 (Jen)

= 3n/4 + 1

= (3n + 4) / 4

so (3n + 4) / 4 = 4n/5

=> 3n + 4 = 4n/5 * 4

=> (3n + 4) * 5 = 16n

=> 15n + 20 = 16n

=> 20 = n

=> n = 20

So total students registered for class is 20

today no of people absent = n/5 = 20/5 = 4

8 0
3 years ago
Brittany bought 3 bracelets and 2 necklaces for $21. Each bracelet cost $5. The necklaces were all the same price. What is the c
Kipish [7]

Answer:

The cost for 1 necklace is $3.

Step-by-step explanation:

With the information provided, you can say that the amount spent in bracelets and necklaces is equal to the price per bracelet for the number of bracelets plus the price per necklace for the number of necklaces, which is:

c=3x+2y, where:

c is the total cost

x is the price per bracelet

y is the price per necklace

Now, you can say that c=21 and x=5 and solve for y to find the price per necklace:

21=(3*5)+2y

21=15+2y

21-15=2y

6=2y

y=6/2

y=3

According to this, the answer is that the cost for 1 necklace is $3.

7 0
3 years ago
Regular Sire (12 ounces)
worty [1.4K]
0.27 per ounce for regular
And
0.26 per ounce for family
7 0
3 years ago
What is a30 for the arithmetic sequence presented in the table below?
Xelga [282]
\bf \begin{array}{ll}&#10;n&a_n\\&#10;\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\&#10;6&50\\&#10;7&50+d\\&#10;8&50+d+d\\&#10;9&50+d+d+d\\&#10;10&50+d+d+d+d\\&#10;11&50+d+d+d+d+d\\&#10;&35&#10;\end{array}&#10;\\\\\\&#10;50+5d=35\implies 5d=-15\implies d=\cfrac{-15}{5}\implies d=-3&#10;\\\\\\&#10;\textit{we know d = -3, and we know }a_{11}=35\qquad thus

\bf n^{th}\textit{ term of an arithmetic sequence}\\\\&#10;a_n=a_1+(n-1)d\qquad &#10;\begin{cases}&#10;n=n^{th}\ term\\&#10;a_1=\textit{first term's value}\\&#10;d=\textit{common difference}\\&#10;----------\\&#10;d=-3\\&#10;n=11\\&#10;a_{11}=35&#10;\end{cases}&#10;\\\\\\&#10;a_{11}=a_1+(11-1)(-3)\implies 35=a_1+(11-1)(-3)&#10;\\\\\\&#10;35=a_1-30\implies 65=a_1

now we know what "d" is, and what a₁ is, so let's check the 30th term,

\bf n^{th}\textit{ term of an arithmetic sequence}\\\\&#10;a_n=a_1+(n-1)d\qquad &#10;\begin{cases}&#10;n=n^{th}\ term\\&#10;a_1=\textit{first term's value}\\&#10;d=\textit{common difference}\\&#10;----------\\&#10;d=-3\\&#10;n=30\\&#10;a_{1}=65&#10;\end{cases}&#10;\\\\\\&#10;a_{30}=65+(30-1)(-3)\implies a_{30}=65-87\implies a_{30}=-22
8 0
4 years ago
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