All categories

3 years ago

Give the coordinates of a point on the line whose equation in point-slope form is y − (−4) = 1 2 (x − 6).

1 answer:

8 0

I'm assuming that the equation should read y - (-4) = 1/2(x-6)

If so, then the equation is in the form
y-y1 = m(x-x1)
Notice how the slope m matches up with 1/2. So the slope is 1/2

Also notice that x1 and y1 match up with 6 and -4 respectively

This means the point (6,-4) is on the line

Answer: (6,-4)

You might be interested in

What is the area of this triangle?

Lapatulllka [165]

Area is 1/2•b•h so 25

7 0

3 years ago

PLEASE HELP ITS DUE TODAY!!! Write an equation in which the quadratic expression 2x^2-2x 12 equals 0. Show the expression in fac

stepladder [879]

This is the function

${2x}^{2} - 2 {x}^{1} + 12$

Then factor 2 out

$2(x^2- x + 6) = 0$

Divide both side by two and use the quadratic formula to get the following

$(x - 3)(x + 2) = 0$

X=3 And x=-2 and don't forget to Chek them

3 0

3 years ago

A supporting goods store sells 2 fishing reels and 5 fishing rods for $243. Later, they still 8 fishing reels and 6 fishing rods

Gwar [14]

To answer this, you can set up a system of equations. Solve for one of the variables and substitute this new equation into the 2nd equation.

2x + 5y = 243 - I'll solve this one for x.
8x + 6y = 538

2x + 5y = 243
2x = 243 - 5y
2 2
x = 121.5 - 2.5y ; substitute this in for x in the second equation

8x + 6y = 538
8 (121.5 - 2.5y) + 6y = 538
972 - 20y + 6y = 538
972 - 14y = 538
-972 -972
-14y = -434
-14 -14
y = 31

The cost of a rod (y) is $31. 

x = 121.5 - 2.5y
x = 121.5 - 2.5 x 31
x = 44

The cost of a reel(x) is $44.

5 0

3 years ago

Read 2 more answers

Determine the asymptotes of the function: y=x^3-5x^2+4x-25/x^2-4x+3

igomit [66]

Answer:

Vertical A @ x=3 and x=1

Horizontal A nowhere since degree on top is higher than degree on bottom

Slant A @ y=x-1

Step-by-step explanation:

I'm going to look for vertical first:

I'm going to factor the bottom first: (x-3)(x-1)

So we have possible vertical asymptotes at x=3 and at x=1

To check I'm going to see if (x-3) is a factor of the top by plugging in 3 and seeing if I receive 0 (If I receive 0 then x=3 gives me a hole)

3^3-5(3)^2+4(3)-25=-31 so it isn't a factor of the top so you have a vertical asymptote at x=3

Let's check x=1

1^3-5(1)^2+4(1)-25=-25 so we have a vertical asymptote at x=1 also

There is no horizontal asymptote because degree of top is bigger than degree of bottom

There is a slant asympote because the degree of top is one more than degree of bottom (We can find this by doing long division)

x -1

--------------------------------------------------

x^2-4x+3 | x^3-5x^2+4x-25

- ( x^3-4x^2+3x)

--------------------------------

-x^2 +x -25

- (-x^2+4x-3)

---------------------

-3x-22

So the slant asymptote is to x-1

8 0

3 years ago

the radius of a circular candle is 5mm. if i want to attach a ribbon to the outside, how much ribbon do i need? (answer choices

Oxana [17]

Answer:

18.84

PLEASE MARK BRAINLIEST!! THX

Step-By-Step EXPLAINATION:

radius: 6 ft

3.14*6=

18.84

7 0

3 years ago