Question

(-1/8c+16)-(3/8+3c)=

Answer 1

Answer:

$-3.125c+15.625$

Step-by-step explanation:

We have the expression

$(-\frac{1}{8}c+16)-(\frac{3}{8}+3c )$

First we eliminate the parenthesis by multiplying the second parenthesis by the negative.

$-\frac{1}{8}c+16-\frac{3}{8}-3c$

and now we put together similar terms, adding the terms that contain $c$:

$(-\frac{1}{8}-3)c+16-\frac{3}{8}$

$(-\frac{1}{8}-\frac{3}{1})c+16-\frac{3}{8}$

$(\frac{(-1)(1)-(3)(8)}{8(1)})c+16-\frac{3}{8}$

$(\frac{(-1-24)}{8})c+16-\frac{3}{8}$

$\frac{-25}{8}c+16-\frac{3}{8}$

and now we put together the independent quantities:

$\frac{-25}{8}c+\frac{16}{1} -\frac{3}{8}$

$\frac{-25}{8}c+\frac{16(8)-3(1)}{8}$

$\frac{-25}{8}c+\frac{128-3}{8}$

$\frac{-25}{8}c+\frac{125}{8}$

And if we convert the fractions to decimals we have:

$-3.125c+15.625$

Answer 2

(-1/8 c+16)-(3/8+3c)=

= -1/8c + 16 - 3/8 - 3c

= (-1/8 c - 3c) + (16 - 3/8)

= (1/8 c - 24/8 c) + (128/8 - 3/8)

= - 23/8 c + 125/8