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sladkih [1.3K]
2 years ago
7

What is this ratio in simplest form? 16:64 A.1:4 B.2:8 C.4:1 D.8:32

Mathematics
1 answer:
iren2701 [21]2 years ago
8 0

Answer: A. 1:4

Step-by-step explanation: 16/64 = 0.25, 1/4 = 0.25, so it is A.

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Whats the circumference of a circle with a radius of 21 meters
Bogdan [553]

Answer:

C =131.88 meters

Step-by-step explanation:

The circumference of a circle is given by

C = 2*pi*r

where r is the radius

C = 2 * pi * 21

C = 42 pi

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C = 42(3.14)

C =131.88 meters

7 0
3 years ago
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Find the area of EBCD using (a) and (b).
ioda

I hope this helps you

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3 years ago
If the squared difference of the zeroes of the quadratic polynomial x2+kx+30 is equal to 169 find the value of k and the zeroes
anyanavicka [17]

ANSWER

x  =  2 \: \: or \:  \:  x  =  15

Or

x  =   - 2 \: \: or \:  \:  x  =   -  15

EXPLANATION

The given polynomial is

f(x) = {x}^{2}  + kx + 30

where a=1,b=k, c=30

Let the zeroes of this polynomial be m and n.

Then the sum of roots is

m + n =  -  \frac{b}{a}  =  -k

and the product of roots is

mn =  \frac{c}{a}  = 30

The square difference of the zeroes is given by the expression.

( {m - n})^{2} =  {(m + n)}^{2} - 4mn

From the question, this difference is 169.

This implies that:

( { - k)}^{2}  - 4(30) = 169

{  k}^{2}  -120= 169

k^{2} = 289

k=  \pm \sqrt{289}

k=  \pm17

We substitute the values of k into the equation and solve for x.

f(x) = {x}^{2}   \pm17x + 30

f(x) = (x  \pm2)(x  \pm 15)

The zeroes are given by;

(x  \pm2)(x  \pm 15) = 0

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5 0
3 years ago
(7x + 3)
padilas [110]

Answer:

D or 6

Step-by-step explanation:

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7x = 45 - 3          Combine

7x = 42               Divide by 7

7x/7 = 42/7

x =  6

3 0
2 years ago
NEED ANSWER ASAP REALLY IMPORTANT i will take any of the answers
dedylja [7]

1. \: MC  \: is \:  tangent \:  to \:  (B)\Rightarrow \widehat{BCM}=90° \\ 2. \: MC  \: and \: MZ \: are \:  tangent  \: to  \: (B)\Rightarrow MC = MZ\Leftrightarrow 5x - 9 = x + 7\Leftrightarrow x = 4 \\ 3. \: BM =  \sqrt{ {BC}^{2} + {MC}^{2}  }  =  \sqrt{ {5}^{2} +  {12}^{2}  }  = 13 \\ \Rightarrow EM = BM - BE = BM - BC = 13 - 5 = 8 \\ 4. \:  \tan(60°) = \frac{MC}{BC}  =  \frac{13 \sqrt{3}  }{ BC}\Leftrightarrow BC =  \frac{13 \sqrt{3} }{\tan(60°)} =   \frac{13 \sqrt{3} }{ \sqrt{3} }  = 13 \\ 5. \: MC =  \sqrt{ {BM}^{2}  -  {BC}^{2} }  =  \sqrt{ {20}^{2}  -  {12}^{2} }  = 16 \\ 6. \:BZ =  \sqrt{ {BM}^{2}  -  {MZ}^{2} } =  \sqrt{ {25}^{2}  -  {20}^{2} }  = 15 \\ \Rightarrow XE=BX+BE=BZ+BZ=15+15=30

7 0
3 years ago
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