Answer:
$681.60
Step-by-step explanation:
<u><em>Given:</em></u>
<em>During a sale, a store offered a 20% discount on a TV that originally sold for $710. After the sale, the discounted price of the TV was marked up by 20%</em>
<u><em>To Find:</em></u>
<em>What was the price of the TV after the markup? Round to the nearest cent.</em>
<u><em>Solution:</em></u>
$710 × (1 + 20%) × (1 - 20%)
$710 × 1.2 × (1-0.2)
$710 × 1.2 × 0.8
($710 × 1.2) × 0.8
852 × 0.8
= $681.60
<u><em>Kavinsky</em></u>
Answer:
a) P=0.0225
b) P=0.057375
Step-by-step explanation:
From exercise we have that 15% of items produced are defective, we conclude that probabiity:
P=15/100
P=0.15
a) We calculate the probabiity that two items are defective:
P= 0.15 · 0.15
P=0.0225
b) We calculate the probabiity that two of three items are defective:
P={3}_C_{2} · 0.85 · 0.15 · 0.15
P=\frac{3!}{2!(3-2)!} · 0.019125
P=3 · 0.019125
P=0.057375
The answer selected is the correct answer because all of the other ones are equivalent to each other.
