Suppose that 600 yards of fencing material are available to fence in
1 answer:
Answer:
Length = 150 yards
Width = 100 yards
Step-by-step explanation:
We want 600 yards of fencing that will result in the largest 2 fenced corrals, sharing a common border.
It will take the shape of a rectangle, with a dividing fence down the center.
Let W and L, Width and Length of the larger enclosure.
See attachment.
W= Area of the larger enclosure.
The perimeter is 2W + 2L.
The dividing fence is 1W
We know that we only have 600 yards of fence, so:
2W + 2L + 1W = 600 yards
Area = W x L
---
3W + 2L = 600 (yards)
2L = 600 -3W
L = (600-3W)/2
L = 300 -(3/2)W
---
Use this expression in the Area calculation:
Area = W x L
Area = W x (300 -(3/2)W)
Area = 300W -(3/2)W^2)
To find the maximum area, take the first derivative and set to zero to find the value of W that results in the greatest area.
Area' = 300 -2(3/2)W)
0 = 300 - 3W
3W = 300
W = 100 yards
Since 3W + 2L = 600
L = (600 - 3W)/2
L = (600 - 3(100))/2
L = 150 yards
Area = 150*100 = 15,000 yards^2
You might be interested in
For this case we have that by definition, a function is of the form:
So, we have the following system of equations:
Equating the equations we have:
Adding 2x to both sides of the equation:
Subtracting 2 from both sides of the equation:
Dividing between -4 on both sides of the equation:
Thus, the value of the variable "x" is -0.5.
Answer:
-0.5