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2 years ago

6

Gianna used two refrigerators, each set to a different temperature, to cool two cups of hot liquid

2 answers:

viktelen [127]2 years ago

5 0

The answers are

1). warmer

2). end behavior

3). higher

When Gianna initially placed the two cups in the refrigerators, the liquid placed in refrigerator A was warmer than the liquid placed in refrigerator B.

The end behavior of the two functions implies that refrigerator A is set to a

higher temperature than refrigerator B.

The graph for the question

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ludmilkaskok [199]2 years ago

3 0

Answer:

Whichever refrigerator has the HIGHEST temperature will make the hot liquid cool slower and whichever one has the LOWEST temperature will cool the hot liquid faster

Step-by-step explanation:

EXAMPLE: If one is 55 degrees and the other one is 5 degrees, the one that is 5 degrees will cool the hot liquid faster.

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What is the approximate area of the circle shown below?

Musya8 [376]

Answer:

<h2>B. 5027 in²</h2><h2></h2>

Step-by-step explanation:

Area of a circle = π r²

where r = 80/2 = 40 in

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2 years ago

Find sin2x, cos2x, and tan2x if sinx=-15/17 and x terminates in quadrant III

Paha777 [63]

Given:

$\sin x=-\dfrac{15}{17}$

x lies in the III quadrant.

To find:

The values of $\sin 2x, \cos 2x, \tan 2x$ .

Solution:

It is given that x lies in the III quadrant. It means only tan and cot are positive and others are negative.

We know that,

$\sin^2 x+\cos^2 x=1$

$(-\dfrac{15}{17})^2+\cos^2 x=1$

$\cos^2 x=1-\dfrac{225}{289}$

$\cos x=\pm\sqrt{\dfrac{289-225}{289}}$

x lies in the III quadrant. So,

$\cos x=-\sqrt{\dfrac{64}{289}}$

$\cos x=-\dfrac{8}{17}$

Now,

$\sin 2x=2\sin x\cos x$

$\sin 2x=2\times (-\dfrac{15}{17})\times (-\dfrac{8}{17})$

$\sin 2x=-\dfrac{240}{289}$

We know that,

$\cos 2x=1-2\sin^2x$

$\cos 2x=1-2(-\dfrac{15}{17})^2$

$\cos 2x=1-2(\dfrac{225}{289})$

$\cos 2x=\dfrac{289-450}{289}$

$\cos 2x=-\dfrac{161}{289}$

Using the trigonometric ratios, we get

$\tan 2x=\dfrac{\sin 2x}{\cos 2x}$

$\tan 2x=\dfrac{-\dfrac{240}{289}}{-\dfrac{161}{289}}$

$\tan 2x=\dfrac{240}{161}$

Hence, the required values are $\sin 2x=-\dfrac{240}{289},\cos 2x=-\dfrac{161}{289},\tan 2x=\dfrac{240}{161}$ .

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3 years ago

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jeka57 [31]

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2 years ago

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s344n2d4d5 [400]

441614, rounded to the whole

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2 years ago

Which is closest to the area of a circle that has a radius of 6 cm? Use 3.14

marin [14]

Answer:

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Step-by-step explanation:

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3 years ago