1. x - 16
2. x + 5
3. x divided by 48 (I don’t have the division symbol.)
Answer:
The launch angle should be adjusted to 30.63°
Step-by-step explanation:
The range of a projectile which is the horizontal distance covered by the projectile can be expressed as;
R =(v^2 sin2θ)/g
Where
R = range
v = initial speed
θ = launch angle
g = acceleration due to gravity
For the case above. When the projectile is launched at angle 13° above the horizontal.
θ1 = 13
R1 = (v^2 sin2θ1)/g
R1 = (v^2 sin26°)/g ....1
For the range to double
R2 = (v^2 sin2θ)/g .....2
R2 = 2R1
Substituting R2 and R1
(v^2 sin2θ)/g = 2 × (v^2 sin26°)/g
Divide both sides by v^2/g
sin2θ = 2sin26
2θ = sininverse(2sin26)
θ = sininverse(2sin26)/2
θ = 30.63°
Answer:
y = 4x–5
Step-by-step explanation:
Slope intercept form is y = mx +b. We can rearrange the equation to fit slope intercept form.
–2y = –8x + 10 (we get this by subtracting 8x from both sides)
In order to isolate the y, we divide both sides by –2.
= 
+ 
–2 divided by –2 equals 1, –8 divided by –2 equals 4, and 10 divided by –2 equals 5.
Therefore, the answer is y = 4x–5.
It would be $38 total, because it would be 20 for the adults and 18 for the children
