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Vesnalui [34]
2 years ago
9

the junior class has 50 students. twenty-five students take french, 15 take latin, and 10 take both. if a student is chosen at r

andom from the class, what is the probability that the student chosen takes neither french nor latin?
Mathematics
1 answer:
ivann1987 [24]2 years ago
3 0
P(F) = 0.5
P(L) = 0.3
P(F\cap L)=0.2
P(F\cap L')=0.5-0.2=0.3
P(F'\cap L)=0.3-0.2=0.1
P(F'\cap L')=1-0.3-0.2-0.1=0.4




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For each set of probabilities, determine whether the events A and B are independent or dependent.
lozanna [386]

Answers:

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Explanation:

If events A and B are independent, then the two following equations must both be true

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This is because the conditional probability P(A|B) means "P(A) when B has happened". If B were to happen, then P(A) must be the same as before. In other words, event B does not affect A, and vice versa.

For part (a), we have P(B) = 1/4 and P(B|A) = 1/4 showing that P(B|A) = P(B) is true, and therefore we can say the events are independent. We don't need the info that P(A) = 1/8.

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Unlike part (a), part (b) has the answer "dependent" because P(A) = 1/8 and P(A | B) = 1/3 differ in value. Event A starts off at probability 1/8, but then event B occurring means P(A) gets increased to 1/3. The prior knowledge about B changes the chances of A. The P(B) = 1/5 is unneeded.

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If A and B were independent, then,

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Answer:

4)x= g-c

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7)a=\frac{k}{u}

8)x= \frac{g}{c}

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10)x= \frac{2c+3}{3}

11)a=\frac{n+p}{m}

12)a= \frac{ub}{k}

13)a= d -r + c

14)x=\frac{np}{m}

Step-by-step explanation:

4) g= c+x

x= g-c

5) u=x-k

x =u+k

6)g = c+x

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12)u = \frac{ak}{b} \\\\u*b = ak\\\\a= \frac{ub}{k}

13)a-c = d-r

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