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NemiM [27]
4 years ago
9

Find all the real cube roots of -0.000125

Mathematics
2 answers:
marta [7]4 years ago
4 0

Answer : The real cube roots of -0.000125 is, -0.05

Step-by-step explanation :

Cube root : It is defined as the number which produces a given number when cubed.

For example :

3 cubed is 27, so the cube root of 27 is 3

We Can also cube negative numbers.

For example :

When we cube +5 we get, +125 : (+5) × (+5) × (+5) = +125

When we cube -5 we get, -125 : (-5) × (-5) × (-5) = -125

So, the cube root of -125 is, -5

As we are given the number -0.000125. Now we have to determine the real cube roots of this number.

-0.000125=-\frac{125}{1000000}=-\frac{125}{10^6}

Now taking cube root of this number, we get:

-\sqrt[3]{\frac{125}{10^6}}=-\sqrt[3]{\frac{(5)^3}{10^6}}=-\frac{5}{10^2}=-0.05

Thus, the real cube roots of -0.000125 is, -0.05

Arturiano [62]4 years ago
3 0
We calculate the cube root, 

we know that

-0.000125-------------> is equal to -125/1000000-------->(-5³/10<span>^6)
</span>∛(-5³/10^6) = -5/10^2-------> -5/100--------> -0.05

The answer is 
-0.05
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Find parametric equations for the tangent line to the curve with the given parametric equations at the specified point. Illustra
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x = t

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r(t) = (x,y,z)

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The tangent line passes through (0, 1, 0) and the tangent line is parallel to r'(0)

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The parametric equations for the tangent line are:

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y = 1 - t

z = 2t

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