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3 years ago

Which method is valid for proving that two circles are similar?

1 answer:

4 0

First I'm going to go through the choices with you and evaluate
each one. Then after that, I'm going to hand you a secret that
I promise is going to knock your socks off.

a- Calculate the ratio of the diameter to the radius for each circle
and show that they are equal.
-- That won't tell you anything. The ratio of the diameter
to the radius of EVERY circle is 2 .

b- Calculate the ratio of degrees to the circumference for each circle
and show that they are equal.
-- That doesn't tell you anything. The circumference
of EVERY circle subtends a central angle of 360°.

c- Calculate the ratio of the área to the circumference for each circle
and show that they are equal.
-- That doesn't tell you anything. The ratio of the area
to the circumference of EVERY circle is (radius/2).
They're only equal if the circles are the same size.

d- Calculate the ratio of the diameter to the circumference for each circle
and show that they are equal.
-- That doesn't tell you anything. The ratio of the diameter
to the circumference of EVERY circle is 1/pi. If the ratio isn't
1/pi, then you're not looking at a circle.

None of these choices tells you whether the two circles are similar.
What are you going to do ? How can you tell ? ?

Here's the surprise I promised you.
Beware of flying socks:

All circles are similar to all other circles.

Good night.

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Select True or False for each statement.

mote1985 [20]

<h2>Answer:</h2>

For a real number a, a + 0 = a. TRUE

For a real number a, a + (-a) = 1. FALSE

For a real numbers a and b, | a - b | = | b - a |. TRUE

For real numbers a, b, and c, a + (b ∙ c) = (a + b)(a + c). FALSE

For rational numbers a and b when b ≠ 0, is always a rational number. TRUE

<h2>Explanation:</h2>

<u>For a real number a, a + 0 = a. </u><u>TRUE</u>

This comes from the identity property for addition that tells us that<em> zero added to any number is the number itself. </em>So the number in this case is $a$ , so it is true that:

$a+0=a$

For a real number a, a + (-a) = 1. FALSE

This is false, because:

$a+(-a)=a-a=0$

For any number $a$ there exists a number $-a$ such that $a+(-a)=0$

For a real numbers a and b, | a - b | = | b - a |. TRUE

This is a property of absolute value. The absolute value means remove the negative for the number, so it is true that:

$\mid a-b \mid= \mid b-a \mid$

For real numbers a, b, and c, a + (b ∙ c) = (a + b)(a + c). FALSE

This is false. By using distributive property we get that:

$(a + b)(a + c)=a^2+ac+ab+bc \\ \\ a^2+ab+ac+bc \neq a+(b.c)$

For rational numbers a and b when b ≠ 0, is always a rational number. TRUE

A rational number is a number made by two integers and written in the form:

$\frac{u}{v} \\ \\ v \neq 0$

Given that $a \ and \ b$ are rational, then the result of dividing them is also a rational number.

7 0

3 years ago

Read 2 more answers

The sophomore class is putting on a dinner and dance to raise money for when they have their prom. From their freshman year they

malfutka [58]

They need to sell 300 tickets in order to make$1200

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3 years ago

Help with my homework

irinina [24]

The answer is B, there’s no solution.

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2 years ago

A rectangle is formed by 2 congruent right triangles. The area of each triangle is 6 in^2. If each side of the rectangle is a wh

abruzzese [7]

How sad. You were going along so nicely there, with a fascinating problem
that would be fun to work on, and then you suddenly fell off over the edge.

"Which of these ..." always means "Here's a list of choices. Pick out the
correct answer from the list." So we know that there was a list of choices
right there, where you copied the question from. But when you finished
copying the question and reached the list of choices, you stopped there,
never copied the list, and went away to do something else instead.

Without that list, there's no way for us to answer the question "Which of these...".

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3 years ago

Suppose the six people consist of three mar- ried couples and each couple wants to sit together with the older partner on the le

chubhunter [2.5K]

6 possible ways to order 3 couples in a row

Given,

We have three married couples. that is six persons in total.

a, b, c, d, e, f may taken as the six persons.

Considering the statement:

Elder partner on the left, assume a, c and e as elders.

Then we have, (a, b) ------ ( 1)

(c, d) ------ (2)

(e, f) ------ (3)

There is no change in position between the couples.

So, we get three persons in total.

Possible ways to order these three persons will be like this: 3! = 3×2×1

= 6

Learn more about seating arrangement here ; brainly.com/question/10702719

#SPJ4

4 0

2 years ago