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ExtremeBDS [4]
3 years ago
13

Parallel and Perpendicular Equations (help! 40 points!)

Mathematics
2 answers:
wlad13 [49]3 years ago
8 0

Answer:

3y - 7x = - 9

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

y = - \frac{3}{7} x - 1 ← is in slope- intercept form

with slope m = - \frac{3}{7}

Given a line with slope m then the slope of a line perpendicular to it is

m_{perpendicular} = - \frac{1}{m} = - \frac{1}{-\frac{3}{7} } = \frac{7}{3}

Rearrange the given equations to find which slope matches m = \frac{7}{3}

Consider 3y - 7x = - 9

Add 7x to both sides

3y = 7x - 9 ( divide all terms by 3 )

y = \frac{7}{3} x - 3 ← in slope- intercept form

with slope = \frac{7}{3}

Thus 3y - 7x = - 9 represents a perpendicular line

PolarNik [594]3 years ago
4 0

Answer:

Step-by-step explanation:

y=mx+c

So in this case, m is (-3/7), which is the slope.

(-3/7)(another slope)=-1

Another slope=3/7

A. The slope is -7/3

B. The slope is 3/7

C. The slope is -7/3

D. The slope is -3/7

Thus, the answer is the bottom of the left hand side, which is 3x-7y=14

Hope it helps!!! Good luck!!

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Assume that SAT scores are normally distributed with mean 1518 and standard deviation 325. Round your answers to 4 decimal place
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Answer:

a. 0.2898

b. 0.0218

c. 0.1210

d. 0.1515

e. This is because the population is normally distributed.

Step-by-step explanation:

Assume that SAT scores are normally distributed with mean 1518 and standard deviation 325. Round your answers to 4 decimal places

We are using the z score formula when random samples

This is given as:

z = (x-μ)/σ/√n

where x is the raw score

μ is the population mean

σ is the population standard deviation.

n is the random number of samples

a.If 100 SAT scores are randomly selected, find the probability that they have a mean less than 1500.

For x = 1500, n = 100

z = 1500 - 1518/325/√100

z = -18/325/10

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Probability value from Z-Table:

P(x<1500) = 0.28984

Approximately = 0.2898

b. If 64 SAT scores are randomly selected, find the probability that they have a mean greater than 1600

For x = 1600, n = 64

= z = 1600 - 1518/325/√64.

z= 1600 - 1518 /325/8

z = 2.01846

Probability value from Z-Table:

P(x<1600) = 0.97823

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Approximately = 0.0218

c. If 25 SAT scores are randomly selected, find the probability that they have a mean between 1550 and 1575

For x = 1550, n = 25

z = 1550 - 1518/325/√25

z = 1550 - 1518/325/5

z = 1550 - 1518/65

= 0.49231

Probability value from Z-Table:

P(x = 1550) = 0.68875

For x = 1575 , n = 25

z = 1575 - 1518/325/√25

z = 1575 - 1518/325/5

z = 1575 - 1518/65

z = 0.87692

Probability value from Z-Table:

P(x=1575) = 0.80974

The probability that they have a mean between 1550 and 1575

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d. If 16 SAT scores are randomly selected, find the probability that they have a mean between 1440 and 1480

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z = 1440 - 1518/325/√16

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Probability value from Z-Table:

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For x = 1480, n = 16

z = 1480 - 1518/325/√16

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Probability value from Z-Table:

P(x = 1480) = 0.32

The probability that they have a mean between 1440 and 1480

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Approximately = 0.1515

e. In part c and part d, why can the central limit theorem be used even though the sample size does not exceed 30?

The central theorem can be used even though the sample size does not exceed 30 because the population is normally distributed.

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