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Ksivusya [100]
4 years ago
5

The population of Hinchton in 1991 was 22,374. In 1987 the population was only 14,998. How much did the population increase betw

een 1987 and 1991?
Mathematics
1 answer:
nlexa [21]4 years ago
7 0
My final answer is 7,376 degrees, increase. 
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Mice21 [21]
You can add 8, eight times
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What is the solution to this equation?<br> 4(4x + 1) = 3x - 46 - x) + 8
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Answer: Hello There!................

x=-3.5

Step-by-step explanation:

Mark me brainest please. Hope this helps. Anna ♥

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3 years ago
Angle 1 and Angle 2 are supplementary angles. Find x and the measure of Angle 1.
tia_tia [17]

Answer:

The answer to x=18 and angle 1 is 102

Step-by-step explanation:

5 0
3 years ago
If S_1=1,S_2=8 and S_n=S_n-1+2S_n-2 whenever n≥2. Show that S_n=3⋅2n−1+2(−1)n for all n≥1.
Snezhnost [94]

You can try to show this by induction:

• According to the given closed form, we have S_1=3\times2^{1-1}+2(-1)^1=3-2=1, which agrees with the initial value <em>S</em>₁ = 1.

• Assume the closed form is correct for all <em>n</em> up to <em>n</em> = <em>k</em>. In particular, we assume

S_{k-1}=3\times2^{(k-1)-1}+2(-1)^{k-1}=3\times2^{k-2}+2(-1)^{k-1}

and

S_k=3\times2^{k-1}+2(-1)^k

We want to then use this assumption to show the closed form is correct for <em>n</em> = <em>k</em> + 1, or

S_{k+1}=3\times2^{(k+1)-1}+2(-1)^{k+1}=3\times2^k+2(-1)^{k+1}

From the given recurrence, we know

S_{k+1}=S_k+2S_{k-1}

so that

S_{k+1}=3\times2^{k-1}+2(-1)^k + 2\left(3\times2^{k-2}+2(-1)^{k-1}\right)

S_{k+1}=3\times2^{k-1}+2(-1)^k + 3\times2^{k-1}+4(-1)^{k-1}

S_{k+1}=2\times3\times2^{k-1}+(-1)^k\left(2+4(-1)^{-1}\right)

S_{k+1}=3\times2^k-2(-1)^k

S_{k+1}=3\times2^k+2(-1)(-1)^k

\boxed{S_{k+1}=3\times2^k+2(-1)^{k+1}}

which is what we needed. QED

6 0
3 years ago
What do you know about a triangle with an adjacent leg to hypotenuse ratio value of 0.839?
Drupady [299]

Step-by-step explanation:

Use soh cah toa to solve

it is cos(α)=.839

so the angle of α is 32.9653

Hope that helps :)

4 0
3 years ago
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