uh, solve for x? Its simple, but first, since it is a prep for a test, you should study how to solve for x, which is easy. So To solve for x, bring the variable to one side, and bring all the remaining values to the other side by applying arithmetic operations on both sides of the equation. Simplify the values to find the result.
Let’s start with a simple equation as, x + 2 = 7
How do you get x by itself?
Subtract 2 from both sides
⇒ x + 2 - 2 = 7 - 2
⇒ x = 5
Now, check the answer, x = 5 by substituting it back into the equation. We get 5 + 2= 7.
L.H.S = R.H.S
And then for a triangle:
Solve for x" the unknown side or angle in atriangle we can use properties of triangle or thePythagorean theorem.
Let us understand solve for x in a triangle with the help of an example.
△ ABC is right-angled at B with two of its legs measuring 7 units and 24 units. Find the hypotenuse x.
then in △ABC by using the Pythagorean theorem,
we get AC2 = AB2 + BC2
⇒ x2 = 72 + 242
⇒ x2 = 49 + 576
⇒ x2 = 625
⇒ x = √625
⇒ x = 25 units
get it? Good
I think its saying find a side that has no numbers or has a letters. figure out the whole shape then subtract the sides we do know and theres your answer. And if its a decimal round the decimal to the nearest tenth
Answer:
0.1319 or 13.2%
Step-by-step explanation:
You can solve this using the binomial probability formula.
The fact that "obtaining at least two 6s" requires you to include cases where you would get three and four 6s as well.
Then, we can set the equation as follows:
P(X≥x) = ∑(k=x to n) C(n k) p^k q^(n-k)
n=4, x=2, k=2
when x=2 (4 2)(1/6)^2(5/6)^4-2 = 0.1157
when x=3 (4 3)(1/6)^3(5/6)^4-3 = 0.0154
when x=4 (4 4)(1/6)^4(5/6)^4-4 = 0.0008
Add them up, and you should get 0.1319 or 13.2% (rounded to the nearest tenth)
Answer:
Step-by-step explanation:
The average value theorem sets:
if f (x) is continuous in [a, b] and derivable in (a, b) there is a c Є (a, b) such that
, where
f(a)=f(π/2)=-4*sin(π/2) = -4*1= -4
f(b)=(3π/2)=-4*sin(3π/2) = -4*-1 = 4
⇒
c≅130
Answer:
Should be D.
I don't know why it won't let me respond with under 20 characters.
