A) Probability that at least one of these golfers makes a hole in one on the 10th hole at the same tournament is
<span>=1−(<span>2493/2494</span><span>)^<span>5
=1-(0.99)^5
= 1- 0.96
=0.4
b) T</span></span></span><span>he probability that all of these golfers make a hole-in-one on the 10th hole at the same tournament
=</span>(<span>1/2494</span><span>)<span>5
</span></span>
which is nearly zero.
Answer:
2.718 28...
Step-by-step explanation:
the value of e use in solving logarithm is 2.718
91.5 is the perimeter. It's just 5a.
