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Aleksandr-060686 [28]
3 years ago
6

How do you write 23.5 in word form

Mathematics
2 answers:
snow_lady [41]3 years ago
7 0
Twenty three and a half
vladimir1956 [14]3 years ago
5 0

We have the following number:


23.5


This number can be written as:


23 + 0.5


Or:


23 + 1/2


So, the new expression gives us two new numbers. In this way, we can say that:


23 = Twenty three

1/2 = a half


In conclusion, the number 23.5 can be written as follows:


<em>23.5 = Twenty three and a half</em>

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Solnce55 [7]
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8 + 5 = 13 not 12
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Hi! Could you help me me out and solve these two problems? "eight less than the product of seven and xxx", and "the sum of six a
Ann [662]

Given:

The given statement are:

a. Eight less than the product of seven and x.

b. The sum of six and the product of three and d.

To find:

The expression for the given statements.

Solution:

a.

Product of 7 and x is 7×x = 7x.

Eight less than the product of seven and x is 7x - 8.

Therefore, the required expression for the statement "Eight less than the product of seven and x" is 7x-8.

b.

Product of 3 and d is 3×d = 3d.

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Therefore, the required expression for the statement "The sum of six and the product of three and d" is 6+3d.

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2 years ago
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Darya [45]

Answer:

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Step-by-step explanation:

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5 0
3 years ago
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Alika [10]

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Finding an irrational number between which given pair of numbers supports the idea that irrational numbers are dense
Fittoniya [83]

Answer:

3.33 and 1/3

Step-by-step explanation:

"Dense" here means that there are infinite irrational numbers between two rational numbers. Also, there are infinite rational numbers between two rational numbers. That's the meaning of dense. Actually, that can be apply to all real numbers, there always is gonna be a number between other two.

But, to demonstrate that irrationals are dense, we have to based on an interval with rational limits, because the theorem about dense sets is about rationals, and the dense irrational set is a deduction from it. That's why the best option is 2, because that's an interval with rational limits.

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