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3 years ago

I need help ASAP!!! will give brainliest!!

Mathematics

1 answer:

Elena L [17]3 years ago

5 0

The answer is the first choice

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I need help with this

BigorU [14]

no u can only buy 6, or u dont have enough money for 7

6 0

3 years ago

What is the following sum in simplest form sqrt8+3sqrt2+sqrt32 please HURRY

iragen [17]

Answer:

9sqrt2.

Step-by-step explanation:

sqrt8 + 3sqrt2 + sqrt32

= sqrt4 * sqrt2 + 3 sqrt2 + sqrt16 * sqrt2

= 2sqrt2 + 3sqrt2 + 4 sqrt2

= 9 sqrt2.

3 0

3 years ago

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Find the length of side X.

UkoKoshka [18]

Answer:

Step-by-step explanation:

1: $\sqrt{3}$ = x : 4 $\sqrt{3}$

7 0

3 years ago

In problem solve the given differential equation by underdetermined coefficients y''-2y+y=xe^x

Alexus [3.1K]

Answer:

Solution is $y(t)=C_1e^x+C_2xe^x+\frac{x^3e^x}{6}$

Step-by-step explanation:

Given Differential Equation,

$y"-2y'+y=xe^x$ ...............(1)

We need to solve the given differential equations using undetermined coefficients.

Let the solution of the given differential equation is made up of two parts. one complimentary solution and one is particular solution.

$\implies\:y(x)=y_c(x)+y_p(x)$

For Complimentary solution,

Auxiliary equation is as follows

m² - 2m + 1 = 0

( m - 1 )² = 0

m = 1 , 1

So,

$y_c(x)=C_1e^x+c_2xe^x$

Now for particular solution,

let $y_p(x)=Ax^3e^x$

$y'=Ax^3e^x+3Ax^2e^x$

$y"=Ax^3e^x+6Ax^2e^x+6Axe^x$

Now putting these values in (1), we get

$Ax^3e^x+6Ae^2e^x+6Axe^x-2(Ax^3e^x+3Ax^2e^x)+Ax^3e^x=xe^x$

$Ax^3e^x+6Ae^2e^x+6Axe^x-2Ax^3e^x-6Ax^2e^x+Ax^3e^x=xe^x$

$6Axe^x=xe^x$

$6A=1$

$A=\frac{1}{6}$

$\implies\:y_p(x)=\frac{x^3e^x}{6}$

Therefore, Solution is $y(t)=C_1e^x+C_2xe^x+\frac{x^3e^x}{6}$

8 0

4 years ago

_ Explain how 0.5 and 0.5 are different. Which is greater.

My name is Ann [436]

They aren't different. They are they same. Mistype?

8 0

4 years ago

Read 2 more answers