Question

For which value of θ is tan θ equal to sin θ?

Answer 1

Answer:

Step-by-step explanation:

$tan \theta=sin \theta\\tan~ \theta-sin~ \theta=0\\\frac{sin ~\theta}{cos~\theta} -sin\theta=0\\multiply ~by~cos~\theta\\sin ~\theta-sin~\theta~cos~\theta=0\\sin \theta(1-cos \theta)=0\\sin~\theta=0=sin k\pi \theta=k \pi ,where~k~is~an~integer.\\or cos\theta=1=cos 2k\pi \\\theta=2k\pi \\where~k~ is~an ~integer.\\combining\\\theta=k\pi \\where~k~is~an~integer.$