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aksik [14]
4 years ago
14

Charlie wants to order lunch for his friends. He'll order 6 sandwiches and a $3 kid's meal for his little brother. Charlie has $

27. How much can he spend on each sandwich if they are all the same price? Which inequality equation models this situation best?
6x + 3 ≥ 27
or
6x + 3 ≤ 27
Mathematics
1 answer:
Oksana_A [137]4 years ago
6 0

Answer:

6x + 3 ≤ 27

Step-by-step explanation:

Charlie has a maximum amount of $27, meaning he can only spend up to that amount or less.

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Garrett ran 21 1/2 miles last week. He ran
Aneli [31]

Answer:

39 3/8

Step-by-step explanation:

4 0
3 years ago
The decimal .67 can be written as which fraction? A) 67 10,000 B) 67 1,000 C) 67 100 D) 67 10
ss7ja [257]
That would be C because there are two zeros right?
So you move two decimal places from 67.
And you get 0.67
5 0
3 years ago
Read 2 more answers
How does adding the log together automatically mean that it is a factorial?
andreyandreev [35.5K]

Answer: The answer is given below.

Step-by-step explanation:  We are given an equality involving logarithm and we are to show the implication of L.H.S. to R.H.S.

We will be using the following two properties of logarithm:

(i)~\log_ba=\dfrac{1}{\log_ab},\\\\\\(ii)~log_ab+\log_ac=\log_a(bc).

The proof is as follows:

L.H.S.\\\\\\=\dfrac{1}{\log_2N}+\dfrac{1}{\log_3N}+\dfrac{1}{\log_4N}+\cdots+\dfrac{1}{\log_{100}N}\\\\\\=\log_N2+\logN3+\log_N4+\cdots+\log_N100\\\\=\log_N\{2.3.4...100\}\\\\=\log_N\{1.2.3.4...100\}\\\\=\log_N{100!}\\\\=\dfrac{1}{\log_{100!}N}\\\\=R.H.S.

Hence proved.

6 0
3 years ago
suppose you rent a limousine for a formal reception. The bill for the efenimg evening is $53.00. A tax of 6% will be added and y
dangina [55]
Okay when doing percentages remember 6% of 100%

so in decimal form it looks like 0.06

0.06 x 53.00

then you would find 20% of 53.00  53.00 x .20

so then add 53 + .2(53) + .06(53) = 65.72
7 0
4 years ago
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The estimated velocity v (in miles per hour) of a car at the end of a drag race is v = 234 √p ÷ w 3 , where p is the horsepower
Anastaziya [24]

Answer:

The velocity of the car at the end of drag race is 183 miles per hour.

Step-by-step explanation:

We are given the following in the question:

v = 234 \bigg(\dfrac{p}{w}}\bigg)^{\frac{1}{3}}

where v is the velocity of the car at the end of drag race, p is the horsepower of the car and w is the weight of car.

We need to approximate velocity of the car at the end of a drag race when car has a horsepower of 1311 and weighs 2744 pounds.

Putting values in the equation, we get,

v = 234\bigg(\dfrac{1311}{2744}\bigg)^{\frac{1}{3}}\\\\v = 182.93\\v\approx 183\text{ miles per hour}

Thus, the velocity of the car at the end of drag race is 183 miles per hour.

3 0
4 years ago
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