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yan [13]
3 years ago
9

Write a function named remove_duplicates that takes a list (of numeric and/or string values) and returns a new list with only th

e unique elements from the original. This function assumes that there is at least 1 element in the list and that the list does not contain any sublists. The original list is not modified in any way. The returned list does not have to preserve the order of the original list.
Computers and Technology
1 answer:
Lorico [155]3 years ago
6 0

Answer:

def remove_duplicates(lst):

   no_duplicate = []

   dup = []

   for x in lst:

       if x not in no_duplicate:

           no_duplicate.append(x)

       else:

           dup.append(x)

   for y in dup:

       if y in no_duplicate:

           no_duplicate.remove(y)

   return no_duplicate

Explanation:

Create a function called remove_duplicates that takes one parameter, lst

Create two lists one for no duplicate elements and one for duplicate elements

Create for loop that iterates through the lst. If an element is reached for first time, put it to the no_duplicate. If it is reached more than once, put it to the dup.

When the first loop is done, create another for loop that iterates through the dup. If one element in no_duplicate is in the dup, that means it is a duplicate, remove that element from the no_duplicate.

When the second loop is done, return the no_duplicate

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marusya05 [52]
Configure the Internet connection. 

Configure the wireless router. 

Enable NAT. 

Configure DHCP

Secure the SOHO network.
7 0
3 years ago
What is the process in which a server is partitioned into smaller components virtually
lilavasa [31]

The answer to your question is,

Server virtualization

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3 0
3 years ago
a user reports that his dot matrix printer is printing dark and clear on the left of the paper but that the print is very light
yarga [219]

Answer:

Correctly position the platen of the printer to hold the paper in place.

Explanation:

Since the dot matrix printer is printing dark and clear on the left of the paper but very light on the right side of the paper, it is possible that the paper is not being held properly. So adjusting the platen will hold the paper properly and hence uniform prints on the paper.

Note: Dot matrix printers are printers that print closely related dots to form require texts (shapes) by striking some pins against an ink ribbon.

Some of the parts of these printers are; power supply, carriage assembly, Paper sensor, ribbon, platen and pins.

4 0
3 years ago
What is displayed on the console when running the following program?
Andre45 [30]

Answer:

The answer is "Option A"

Explanation:

In the given java code, a class "Test" is defined, inside the main method try and catch block is used, inside the try block method "p()" is called, that print a message. in this block two catch block is used, that works on "NumberFormatException" and "RuntimeException".  In the method "p" declaration, a string variable "s" is defined, that holds double value, that is "5.6", and converts its value into the wrong integer, and other wrong option can be described as follows:

  • In option B, it is wrong, it is not followed by after call method.
  • In option C, It is not followed by runtime exception, that's why it is incorrect.
  • Option D and Option E both were wrong because they can't give run time and compile-time error.  
6 0
3 years ago
Given the value x=false ,y=5 and z=1 what will be the value of F=(4%2)+2*Y +6/2 +(z&amp;&amp;x)?
Bezzdna [24]
<h2>Answer:</h2>

F = 13

<h2>Explanation:</h2>

Given:

x = false

y = 5

z = 1

F = (4%2)+2*Y +6/2 +(z&&x)

We solve this arithmetic using the order of precedence:

<em>i. Solve the brackets first</em>

=> (4 % 2)

This means 4 modulus 2. This is the result of the remainder when 4 is divided by 2. Since there is no remainder when 4 is divided by 2, then

4 % 2 = 0

=> (z && x)

This means (1 && false). This is the result of using the AND operator. Remember that && means AND operator. This will return false (or 0) if one or both operands are false. It will return true (or 1) if both operands are true.

In this case since the right operand is a false, the result will be 0. i.e

(z && x) = (1 && false) = 0

<em>ii. Solve either the multiplication or division next whichever one comes first.</em>

=> 2 * y

This means the product of 2 and y ( = 5). This will give;

2 * y = 2 * 5 = 10

=> 6 / 2

This means the quotient of 6 and 2. This will give;

6 / 2 = 3

<em>iii. Now solve the addition by first substituting the values calculated earlier back into F.</em>

F = (4%2)+2*Y +6/2 +(z&&x)

F = 0 + 10 + 3 + 0

F = 13

Therefore, the value of F is 13

5 0
3 years ago
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