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3 years ago

(a+bx)(a-bx)=25x-4x^3 find the value of b^-a

1 answer:

8 0

25x - 4x³ can be rewritten as:

x(25 - 4x²) = x(5 + 2x)(5 - 2x)

Therefore a = 5 & b = 2

b^-a = 1 / b^a = 1 / 2^5 = 1/32

Hope that helps

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Estimate each product.solve to check your estimate.40×6

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Well 40 times 6 is 240 which means that you don't have to round.

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3 years ago

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On Monday, a localamburger shop said a combined total of 225 hamburgers and cheeseburgers. The number of cheeseburgers sold was

zheka24 [161]

Answer:

h = hamburgers sold

2h - 72 = 578

2h = 650

2 2

h = 325

There were 72 fewer cheeseburgers sold than hamburgers. That means cheeseburgers = 325 - 72

325 - 72 = 253

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Hope this helps :)

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3 years ago

Can someone help me?

choli [55]

Answer:

Step-by-step explanation:

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3 years ago

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PilotLPTM [1.2K]

Answer: (751.05, 766.95)

Step-by-step explanation:

We know that the confidence interval for population mean is given by :-

$\overline{x}\pm z*\dfrac{\sigma}{\sqrt{n}}$ ,

where $\sigma$ =population standard deviation.

$\overline{x}$ = sample mean

n= sample size

z* = Two-tailed critical z-value.

Given : $\sigma= 20$

n= 42

$\overline{x}=759$

We know that from z-table , the two-tailed critical value for 99% confidence interval : z* =2.576

Now, the 99% confidence interval around the true population mean viscosity :-

$759\pm (2.5760)\dfrac{20}{\sqrt{42}}\\\\=759\pm (2.5760)(3.086067)\\\\=759\pm7.9497=(759-7.9497,\ 759+7.9497)\]\\=(751.0503,\ 766.9497)\approx(751.05,\ 766.95)$

∴ A 99% confidence interval around the true population mean viscosity : (751.05, 766.95)

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3 years ago

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arsen [322]

5/16

You have to simplify both sides of the equation, then isolating the variable.

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3 years ago