Answer: What is the question?
Step-by-step explanation:
What is the question?
Answer:
v = 1/(1+i)
PV(T) = x(v + v^2 + ... + v^n) = x(1 - v^n)/i = 493
PV(G) = 3x[v + v^2 + ... + v^(2n)] = 3x[1 - v^(2n)]/i = 2748
PV(G)/PV(T) = 2748/493
{3x[1 - v^(2n)]/i}/{x(1 - v^n)/i} = 2748/493
3[1-v^(2n)]/(1-v^n) = 2748/493
Since v^(2n) = (v^n)^2 then 1 - v^(2n) = (1 - v^n)(1 + v^n)
3(1 + v^n) = 2748/493
1 + v^n = 2748/1479
v^n = 1269/1479 ~ 0.858
Step-by-step explanation:
Answer:
10/18
Step-by-step explanation:
To convert 1.8 to a reciprocal, you first need to change it into a fraction.
1.8 basically expresses 1 
which equals 
.
Since a reciprocal is just switching the top and bottom of a fraction, your reciprocal of 1.8 will be 
.
You can simplify this if you want, to get 
. Either one is correct.
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2x-3y+7=0 -- add 3y to both sides
3y=2x+7 -- divide by 3
y=2x/3 +7/3
The gradient is 2/3
