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rewona [7]
2 years ago
5

A client has an above-the-knee amputation of the left leg because of arterial insufficiency. to prevent a hip flexion contractur

e, in what position should the nurse periodically place this client?
Biology
2 answers:
beks73 [17]2 years ago
8 0

<span>The nurse should put the client at prone position a couple of times in a day for about 20 minutes to prevent hip flexion contracture. The client can be position in supine but the stump must be elevated for the first 24 hours by uplifting the foot of the bed instead of using pillow. The elevation of residual limb after surgery helps lessen edema and pain by increasing venous return and decreasing venous pooling at the distal portion of the extremity.</span>

frez [133]2 years ago
3 0
The nurse should position the client at a prone position every 3 to 4 hours for 20 to 30 minutes periods. This should be done periodically. Arterial insufficiency is any condition that slows or stops the flow of blood through your arteries. Arteries are blood vessels that circulate blood from the heart to other parts of the body.
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<h3>What is the amount of carbon dioxide in the atmosphere?</h3>

Only 0.04% of the atmosphere is made up of carbon dioxide, and water vapor levels can range from 0% to 4%. However, while being the main greenhouse gas in our atmosphere, water vapor possesses “windows” that let some infrared light pass through without being absorbed.

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What are the three main factors that affect barometric (air) pressure ?
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Temperature

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Moisture or water vapour.

Explanation:

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Varying the enzyme- For a one-substrate, enzyme –catalyzed reaction, double –reciprocal plots were determined for three differen
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A woman with type A blood (whose father was type O) has children with a man that has type O blood. Both individuals are heterozy
Fantom [35]

Answer:

Explanation:

A woman with type A blood (whose father was type O) meaning her genotype is AO mates with

Man that has type O blood (OO genotype)

Both are heterozygous for MN blood group and both also heterozygous for the FUT1 gene controlling the synthesis of the H substance (Hh)- which determines the expression of the A and B antigen.

Cross

A O M N H h

O AO OO M MM MN H HH Hh

O AO OO N MN NN h Hh hh

Type A- 1/2 O-1/2 type M- 1/4 MN-1/2 N- 1/4, type H- 3/4 h-1/4

Type A with M antigen:

1/2*1/4*3/4 = 3/32

Type A with M and N antigens:

1/2*1/2*3/4 = 3/16

Type A with N antigen:

1/2*1/4*3/4 = 3/32

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1/2*1/4*3/4= 3/32

Type O with M and N antigens:

1/2*1/2*3/4 = 3/16

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