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inna [77]
3 years ago
13

Olivia read a book. She started on page 20 and each minute she read 3 minutes. Let g(n) be the page Olivia was on at the beginni

ng of the nth minute. G is a sequence. What kind of sequence is it?write an explicit formula for the sequence.
Mathematics
2 answers:
tankabanditka [31]3 years ago
7 0

Answer:

Arithmetic sequence

g(n) = 3n + 17

Step-by-step explanation:

In the concept of sequence and series, if the difference between consecutive terms is constant, For example;

1,2,3,4,5 . . .nth term

here you can note the difference between each term is 1. This 1 is common difference.

Now formula for Arithmetic sequence is

nth term = a + (n-1)d

Here, nth term is value of any term in the sequence you want to find out.

a is the first term of sequence

d is the common difference between two consecutive terms.

For data given in question,

g(n) is any term or nth term you want to find out

Since in each minute, Olivia is reading three pages, so 3 is the common difference.

Olivia started reading from page 20, so first term or a is 20.

From this data putting in the formula you can have;

g(n) = 20 + (n-1)(3)

g(n) = 20 + 3n-3

g(n) = 3n + 17

miskamm [114]3 years ago
4 0
If you mean each minute she read 3 pages.



If she started on page 20 and read 3 pages every minute, and the answer is how many pages did she read in 9 minutes.
Simple just do 20 x 9.

First step - what’s 2 x 9...18. Now anytime there’s a zero just simplify it by putting the 0 at the end of your answer. So the answer would be 180.

I hope this helped!!!
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navik [9.2K]

Answer:

Option D, 10x^4\sqrt{6} +x^3\sqrt{30x} -10x^4\sqrt{3} -x^3\sqrt{15x}

Step-by-step explanation:

<u>Step 1:  Multiply</u>

<u />(\sqrt{10x^4} -x\sqrt{5x^2} )*(2\sqrt{15x^4} + \sqrt{3x^3})\\ (\sqrt{10 * x^2 * x^2} -x\sqrt{5 * x^2} ) * (2\sqrt{15 * x^2 * x^2} +\sqrt{3 * x^2 * x})\\(x^2\sqrt{10} -x^2\sqrt{5} )*(2x^2\sqrt{15} +x\sqrt{3x}) \\\\

(x^2\sqrt{10}*2x^2\sqrt{15} )+(x^2\sqrt{10}*x\sqrt{3x} ) + (-x^2\sqrt{5} *2x^2\sqrt{15}) + (-x^2\sqrt{5} *x\sqrt{3x}

(2x^4\sqrt{150} ) + (x^3\sqrt{30x}) + (-2x^4\sqrt{75}) + (-x^3\sqrt{15x}  )

2x^4\sqrt{5^2*6} + x^3\sqrt{30x} -2x^4\sqrt{5^2*3} -x^3\sqrt{15x}

10x^4\sqrt{6} +x^3\sqrt{30x} -10x^4\sqrt{3} -x^3\sqrt{15x}

Answer:  Option D, 10x^4\sqrt{6} +x^3\sqrt{30x} -10x^4\sqrt{3} -x^3\sqrt{15x}

6 0
3 years ago
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