This is known as quadratic algebra.
To find it, you can use the quadratic formula but that might take a while.
We can factor it out and get
-3(mx² + mx - 1)
We can then set mx² + mx = 1
It would have no solutions
Edit: Above is wrong! I made the mistake of factoring 3 when it cant be factored.
Here is the solution
mx²-3mx=-3
Divide both by -3
mx²+mx=1
And I really messed this up. Its been a long time since quad. Sorry, but I cant seem to get the answer. Try and look up the quadratic formula and see if you can use that
1/2 - 3/8 = 4/8 - 3/8 = 1/8
you have to find a common denominator before you can subtract. in this case it is 8
7 halve equal ho many wholes?
1 whole = 2 haves
7 ÷ 2 = 3.5
3 wholes are in 7 with 1 half left.
Answer:
24 chairs in each class needed
25 classrooms
700 chairs total
how many extra chairs
chairs will be c
t is total
t= 25×c
opposite of multiplication is division( 25 is multiplying by c) c needs to be alone
25 classrooms times chairs equal total chairs
t is 700
700=25×c
700/25=25/25c
700/25=C
c is 28
so 28 chairs for 25 classrooms
they need 24 chairs per class
so there are 4 extra chairs per class
4×25 is 100
**or just multiply 25 classes and 24 chairs
25 times 24 is 600
there are 700 chairs
100 left over
so 100 extra chairs
As you can probably tell, this is a 30, 60, 90 triangle. That means the degree measures are 30, 60, and 90. These are special triangles. For every 30, 60, 90 triangle in the world, the shorter leg (in your case, x) is ALWAYS two times shorter than the hypotenuse (6). 6/2=3, so x=3. Also, the longer leg for a 30, 60, 90 triangle is always equal to the shorter leg times the square root of 3. So, 3 times the square root of 3 is about 5.2. So, y=5.2. Hope it helps!
