What are the nouns in this sentence?

Mathematics

1 answer:

fgiga [73]2 years ago

3 0

Answer:

A noun is most commonly taught a person, place, or thing and sometimes idea. In this sentence, it would be Magazine, Americans, and carbohydrates. And if smith is also part of the sentence, he is a person, so its also a noun. :) Happy learning friend

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The radius of a truck wheel is 3 ft. what is the approximate circumference if the truck wheel.

Phoenix [80]

Circumference = $2 \pi r$
When you plug that in you should have $(2* \pi ) *3$
Solve that and you have your answer(: I would recommend rounding to the nearest hundreth

8 0

3 years ago

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what power can you write to represent the volume of the cube shown? write the power as an expression with a base and an exponent

sergiy2304 [10]

Answer:

The power for the volume of the cube is '3'.

Exponent form of the volume is $(\frac{1}{3})^3$

Volume of the cube is $\frac{1}{27}$ inch³.

Step-by-step explanation:

We are given,

A cube with side equal to $\frac{1}{3}$ inches.

As we know,

Volume of a cube = $side^{3}$

Thus, we get,

Volume of the given cube is,

Volume = $(\frac{1}{3})^3$

i.e. Volume = $\frac{1}{27}$ inch³

Thus, we have,

The power for the volume of the cube is '3'.

Exponent form of the volume is $(\frac{1}{3})^3$

Volume of the cube is $\frac{1}{27}$ inch³.

4 0

2 years ago

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Martha is late for class, so she races her 75 kg body up a 4.0 meter flight of stairs in only 2.3 seconds. What is Martha’s powe

vovangra [49]

Answer:

$1.3\cdot 10^3\text{ J}$

Step-by-step explanation:

Power is defined by work over time. In physics, work can be defined as the energy transferred over from an applied force over some distance. As a formula:

$W=Fd$ , where F = force applied and d = distance that force is applied over.

*It is worth noting that F must be parallel to the distance travelled. If it is perpendicular, no work is done, and if it is at an angle, find the parallel component and use that for F.

In this case, the force applied must counter the force of gravity on Martha, which is given by $F_g=mg$ , where m = Martha's mass and g = gravitational constant 9.8 m/s/s. Therefore, $F_g=75\cdot 9.8=735\text{ N}$ . Since she raises her body 4.0 meters, the work done must be $W=Fd=735\cdot 4=2940\text{ J}$ .