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Lostsunrise [7]
3 years ago
11

PICTURE INCLUDED!

Mathematics
2 answers:
lilavasa [31]3 years ago
7 0

Answer: The answer is A) The mean remains the same.

Step-by-step explanation: To find the mean you add up the total of numbers, then divide by how many numbers there are.

so, 15+23+24+26+27+35= 150 divided by 6 = 25.

Now without the outliers, 23+24+26+27=100 divided by 4 = 25

So with and without the outliers the mean still stays 25

marusya05 [52]3 years ago
3 0
The mean increases by two.

15+23+24+26+27+35 = 140
140/6 = 23.3

23+24+26+27 = 100
100/4 = 25

The mean roughly increases by 2.
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9 cm
OLEGan [10]

Answer:

∴ ∠BAD = sin^{-1}(0.2044) = 11.8°

Step-by-step explanation:

i) AD = 9 cm

ii) DC = 3 cm

iii) ∠BCD = 35°

iv) Since AB is parallel to DC and ∠ABD = 90°  then we can conclude that ∠BDC = 90°.

v) \frac{BD}{DC}  =  \frac{BD}{3\hspace{0.1cm}cm}  = tan(35) = 0.6128      ∴ BD  = 3 \times 0.6128 = 1.84 cm

vi) ∴ sin(∠ BAD ) = \frac{BD}{AD}      ⇒     sin(∠ BAD ) = \frac{1.84}{9} = 0.2044

     ∴ ∠BAD = sin^{-1}(0.2044) = 11.8°

7 0
4 years ago
a garden table and bench cost $738 combined the garden table costs $88 more than the bench what is the cost of the bench
Viefleur [7K]
Hello 

the answer to this is 

650

becomes we subtract 
88 from 738

738-88 and we get 650

so we get 

650
hope this helps 
4 0
3 years ago
Read 2 more answers
Simplify. Write in scientific notation. 0.5(8 * 10^5). A. 8*5^5. B. 4*5^5. C. 8*10^5. D. 4^10^5
Alika [10]

it would be 4×10^{5}

8 0
3 years ago
Sarah had 28 peaches left at her roadside fruit stand. She went to the orchard and picked more peaches to stock up the stand. Th
Ann [662]

Answer:

32

Step-by-step explanation:

If she started with 28, ad had 50 after she picked, you wold subtract 28 from 50 to find your answer.

4 0
3 years ago
How are the step by step math problem suppose to be for this math problem (-2-8)^2?
Sidana [21]

Answer:

the answer is 100

Step-by-step explanation:

(-2-8)^2

(-2-8)(-2-8)

-2(-2-8)-8(-2-8)

4+16+16+64

20+80

100

6 0
3 years ago
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