3 years ago

2log6+6log2/4log2+log27-log9=2

1 answer:

5 0

(2log6 + 6log2) / (4log2 + log27 - log9) = (log6^2 + log2^6) / (log2^4 + log27 - log9) = (log36 + log 64) / (log 16 + log(27/9)) = log(36 x 64) / (log 16 + log 3) = log 2304 / log(16 x 3) = log 48^2 / log 48 = 2log48 / log 48 = 2.

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