2 years ago

Select the correct answer from each drop-down menu. cos2x-cos4x/sin2x+sin4x cos2x+cos4x/sin2x-sin4x

Mathematics

1 answer:

Anastaziya [24]2 years ago

8 0

I’m sorry I’m answering this to ask a question

Explanation:

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What fraction is 4 hours of a day 45 mins of an hour 240cm3 of a litre

lesya [120]

4 hours of a day

1/6

45 mins of an hour

3/4

240cm3 of a litreliter

240cm3=0.24l

6/25

8 0

2 years ago

PLEASE HELP(Mainly 15 & 16) I can give BRAINLIEST!!!

lisov135 [29]

Answer: sorry I don't get it but the answer for 16 is B sorry

Step-by-step explanation:

What do they teach you they are weird t doesn't make any sense

6 0

3 years ago

Find the product of z1 and z2, where z1 = 7(cos 40° + i sin 40°) and z2 = 6(cos 145° + i sin 145°).

Oduvanchick [21]

For two complex numbers $z_1=re^{i\theta}=r(\cos\theta+i\sin\theta)$ and $z_2=se^{i\varphi}=s(\cos\varphi+i\sin\varphi)$ , the product is

$z_1z_2=rse^{i(\theta+\varphi)}=rs(\cos(\theta+\varphi)+i\sin(\theta+\varphi))$

That is, you multiply the moduli and add the arguments. You have $z_1=7e^{i40^\circ}$ and $z_2=6e^{i145^\circ}$ , so the product is

$z_1z_2=7\times6(\cos(40^\circ+145^\circ)+i\sin(40^\circ+145^\circ)=42(\cos185^\circ+i\sin185^\circ)=42e^{i185^\circ}$