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Inessa [10]
3 years ago
7

Suppose tossing a coin 8 times represents the 8 cups of tea, heads represents a correct identification of what was poured first,

tea or milk, and tails represents an incorrect identification of what was poured first. Select the best conclusion you would draw about whether the woman was just guessing.
A. Repeat the process many times (1000). If 6 correct out of 8 cups rarely occurs, then it is most likely that the woman was just guessing as to what was poured first.
B. Repeat the process many times (1000). If 8 correct out of 8 cups rarely occurs, then it is unlikely that the woman was just guessing as to what was poured first.
C. Repeat the process many times (1000). If 8 correct out of 8 cups rarely occurs, then it is likely that the woman was just guessing as to what was poured first.
D. Repeat the process many times (1000). If 4 correct out of 8 cups rarely occurs, then it is unlikely that the woman was just guessing as to what was poured first.
Mathematics
1 answer:
AysviL [449]3 years ago
5 0

Answer:

A. Repeat the process many times (1000). If 6 correct out of 8 cups rarely occurs, then it is most likely that the woman was just guessing as to what was poured first.

Step-by-step explanation:

Since tossing a coin 8 times implies 8 cups of tea, with the given conditions.

The sample space = 1000

Then;

             \frac{6}{8} × 1000 = 750

If 6 correct out of 8 cups occurs (750 out of 1000), the woman got 750 correctly. Thus it can be inferred that it is likely that she knew what was poured first, either the tea or milk.

But, if 6 correct out of 8 cups rarely occurs (i.e 250 out of 1000), then it is most likely that the woman was just guessing as to what was poured first.

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The given number of balloons, green = 10, purple = 4, red = 5, tie-dye = 2, black = 3, gives;

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b. 25/276

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<h3>How can the different probabilities be calculated mathematically?</h3>

Given parameters;

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Green = 10

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Red = 5

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Black = 3

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b. Probability of popping a red balloon = 5/24

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Probability of popping a red and then a green balloon = 5/24 × 10/23 = 25/276

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The probability, <em>P</em>, is therefore;

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Probability that the first balloon is not a tie-dye = 1 - 1/12 = 11/12

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Probability that the third balloon is not a tie-dye = 20/22 = 10/11

Which gives;

The probability, <em>P</em>, of popping anything but a tie-dye on three consecutive throws is therefore;

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Learn more about probability theory in mathematics?

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