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2 years ago

Complete the pattern 274÷1=

Mathematics

1 answer:

Orlov [11]2 years ago

5 0

The answer 274 because anything divided by one is itself

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Could you please find what x=<br><br><br><br>thank you

pickupchik [31]

4x-1=9x-2
Add 1 to both sides
4x= 9x-1
Subtract 9x from both sides
-5x=-1
Divide both sides by -5
X=-1/-5

6 0

3 years ago

The image is the problem:<br><br><br><br><br> ty :P

vlada-n [284]

Answer: the slope is 2/3

7 0

2 years ago

Solve for A if F=MA and F=10 and M=2.5

gogolik [260]

Answer:

$\boxed{\sf A = 4}$

Given:

F = MA

F = 10

M = 2.5

To Find:

Value of A

Step-by-step explanation:

$\sf Substituting \ values \ of \ F \ and \ M \ in \ F = MA:$

$\sf \implies 10 = 2.5A$

$\sf \implies 2.5A = 10$

$\sf Dividing \ both \ side \ of \ 2.5A = 10 \ by \ 2.5:$

$\sf \implies \frac{2.5}{2.5} A = \frac{10}{2.5}$

$\sf \frac{2.5}{2.5} = 1 :$

$\sf \implies A = \frac{10}{2.5}$

$\sf \frac{4 \times \cancel{2.5}}{ \cancel{2.5}} = 4 :$

$\sf \implies A = 4$

3 0

3 years ago

Read 2 more answers

If -3x–7 =23 then 6x=?

vovangra [49]

Answer:

6x = -60

Step-by-step explanation:

-3x - 7 = 23

-3x = 30

x = -10

6(-10) = -60

8 0

2 years ago

Please help me out :P

Veseljchak [2.6K]

cos θ = $\frac{-4\sqrt{65} }{65}$ , sin θ = $\frac{-7\sqrt{65} }{65}$ , cot θ = 4/7, sec θ = $\frac{-\sqrt{65} }{4}$ , cosec θ = $\frac{-\sqrt{65} }{7}$

<h3>What are trigonometric ratios?</h3>

Trigonometric Ratios are values of all the trigonometric functions based on the value of the ratio of sides in a right-angled triangle.

Sin θ: Opposite Side to θ/Hypotenuse

Tan θ: Opposite Side/Adjacent Side & Sin θ/Cos

Cos θ: Adjacent Side to θ/Hypotenuse

Sec θ: Hypotenuse/Adjacent Side & 1/cos θ

Analysis:

tan θ = opposite/adjacent = 7/4

opposite = 7, adjacent = 4.

we now look for the hypotenuse of the right angled triangle

hypotenuse = $\sqrt{7^{2} + 4^{2} }$ = $\sqrt{49+16}$ = $\sqrt{65}$

sin θ = opposite/ hyp = $\frac{7}{\sqrt{65} }$

Rationalize, $\frac{7}{\sqrt{65} }$ x $\frac{\sqrt{65} }{\sqrt{65} }$ = $\frac{7\sqrt{65} }{65}$

But θ is in the third quadrant(180 - 270) and in the third quadrant only tan and cot are positive others are negative.

Therefore, sin θ = - $\frac{7\sqrt{65} }{65}$

cos θ = adj/hyp = $\frac{4}{\sqrt{65} }$

By rationalizing and knowing that cos θ is negative, cos θ = - $\frac{-4\sqrt{65} }{65}$

cot θ = 1/tan θ = 1/7/4 = 4/7

sec θ = 1/cos θ = 1/ $\frac{4}{\sqrt{65} }$ = - $\frac{-\sqrt{65} }{4}$

cosec θ = 1/sin θ = 1/ $\frac{\sqrt{65} }{7}$ = $\frac{-\sqrt{65} }{7}$

Learn more about trigonometric ratios: brainly.com/question/24349828

#SPJ1

5 0

1 year ago