Between what pair of numbers is the product of 289 and seven

The total surface area of a cuboid is 112cm^2. find the value of x. values given: 10cm and 2cm.

Tatiana [17]

Answer:

x= 5.6

Step-by-step explanation:

we will need to put the information we currently have into an equation:

10•2•x= 112

then multiply 10•2 which equals 20...then the equation wil turn out like this:

20•x=112

now you will isolate the x... but how?? dividing 20 by itslef.. cancelling it out, and if you do one thing to the other side of the equation, you have to do it to the other...

20/20•x=112/20

you will end up with x= 122/20

you can use a calculator for this step, but to practice long division... (check the screen shot thingie)

hope this helped !! ^^

6 0

4 years ago

Find the equation of the line shown

Finger [1]

Answer:

y=x+1

Step-by-step explanation:

As you can see, the slope is clearly 1 and the line starts at (0, 1), which is its y-intercept.

Plug the variables into this formula: y=mx+b, then you will get y=x+1.

3 0

3 years ago

businessText message users receive or send an average of 62.7 text messages per day. How many text messages does a text message

KiRa [710]

Answer:

(a) The probability that a text message user receives or sends three messages per hour is 0.2180.

(b) The probability that a text message user receives or sends more than three messages per hour is 0.2667.

Step-by-step explanation:

Let X = number of text messages receive or send in an hour.

The random variable X follows a Poisson distribution with parameter λ.

It is provided that users receive or send 62.7 text messages in 24 hours.

Then the average number of text messages received or sent in an hour is: $\lambda=\frac{62.7}{24}= 2.6125$ .

The probability of a random variable can be computed using the formula:

$P(X=x)=\frac{e^{-\lambda}\lambda^{x}}{x!} ;\ x=0, 1, 2, 3, ...$

(a)

Compute the probability that a text message user receives or sends three messages per hour as follows:

$P(X=3)=\frac{e^{-2.6125}(2.6125)^{3}}{3!} =0.21798\approx0.2180$

Thus, the probability that a text message user receives or sends three messages per hour is 0.2180.

(b)

Compute the probability that a text message user receives or sends more than three messages per hour as follows:

P (X > 3) = 1 - P (X ≤ 3)

= 1 - P (X = 0) - P (X = 1) - P (X = 2) - P (X = 3)

$=1-\frac{e^{-2.6125}(2.6125)^{0}}{0!}-\frac{e^{-2.6125}(2.6125)^{1}}{1!}-\frac{e^{-2.6125}(2.6125)^{2}}{2!}-\frac{e^{-2.6125}(2.6125)^{3}}{3!}\\=1-0.0734-0.1916-0.2503-0.2180\\=0.2667$

Thus, the probability that a text message user receives or sends more than three messages per hour is 0.2667.

6 0

3 years ago

A daycare charges $115 per week for one child. Each additional child costs $65 for the week. If a family pays $505 for a week, h

valentinak56 [21]

Answer:

7 children

Step-by-step explanation:

$505-$115= $390

$390÷$65= 6

6+1= 7

4 0

3 years ago

6x3 + 8x2 – 2x + 4 and 10x3 + x2 + 11x + 9

balu736 [363]

6x3+8x2-2x+4=30-2x

10x3+x2+11x+9=21+13x

3 0

4 years ago