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2 years ago

What is the slope of the line passing through the points (5, 3) and (5, -9)? *

Mathematics

1 answer:

Mars2501 [29]2 years ago

4 0

Answer:

Slope is 0

Step-by-step explanation: x stood the same so therefore the slope is 0 or infinite

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Please view this imagine & help meee:(

EleoNora [17]

Answer:

20: 9t+12

21: 18x

22: 105x+9

24: 156r

25: 3x+11

26: 25.2x

28: 56a

29: 1.5n

30: 13q

Step-by-step explanation:

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6 0

3 years ago

If there are 2 girls per 3 boys What is<br> the ratio of girls to Boys

Phantasy [73]

Answer:

2:3

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3 0

2 years ago

I need help with this plseeee

WARRIOR [948]

Hun, nothing is attatched. Try to attach something or tell me the problem? I'll try and answer it..

Have a fantasic day/night!

6 0

2 years ago

Read 2 more answers

Find the length of the curve. R(t) = cos(8t) i + sin(8t) j + 8 ln cos t k, 0 ≤ t ≤ π/4

arsen [322]

we are given

$R(t)=cos(8t)i+sin(8t)j+8ln(cos(t))k$

now, we can find x , y and z components

$x=cos(8t),y=sin(8t),z=8ln(cos(t))$

Arc length calculation:

we can use formula

$L=\int\limits^a_b {\sqrt{(x')^2+(y')^2+(z')^2} } \, dt$

$x'=-8sin(8t),y=8cos(8t),z=-8tan(t)$

now, we can plug these values

$L=\int _0^{\frac{\pi }{4}}\sqrt{(-8sin(8t))^2+(8cos(8t))^2+(-8tan(t))^2} dt$

now, we can simplify it

$L=\int _0^{\frac{\pi }{4}}\sqrt{64+64tan^2(t)} dt$

$L=\int _0^{\frac{\pi }{4}}8\sqrt{1+tan^2(t)} dt$

$L=\int _0^{\frac{\pi }{4}}8\sqrt{sec^2(t)} dt$

$L=\int _0^{\frac{\pi }{4}}8sec(t) dt$

now, we can solve integral

$\int \:8\sec \left(t\right)dt$

$=8\ln \left|\tan \left(t\right)+\sec \left(t\right)\right|$

now, we can plug bounds

and we get

$=8\ln \left(\sqrt{2}+1\right)-0$

so,

$L=8\ln \left(1+\sqrt{2}\right)$ ..............Answer

5 0

2 years ago

How many fourth-fifths are in eight

Elenna [48]

Answer:

Step-by-step explanation:

8 ÷ 4/5 = 10

I hope this helps!!

7 0

1 year ago