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3 years ago

If it rained 17 out of the last 60 days.What was the percentage of rainy days ?

Mathematics

2 answers:

Aloiza [94]3 years ago

7 0

28.33%
to find the percent you have to divide the quantity by the whole then times your quotient by 100

Fantom [35]3 years ago

4 0

Out of the 60 days, it rained 10.2% of the time.

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The cheer squad is ordering small towels to throw into the stands at the next pep rally. The printing company has quoted the fol

Nimfa-mama [501]

Answer: C

5x,0<x<20

C(x)={3x+100, x>20

9 0

3 years ago

The line plot (shown in the attached image) shows the prices of sunglasses at a department store.

Andru [333]

a. The median is 70, the mode is 60, and the mean is 70.8.

b. Mean best captures the data.

c. When there are outliers, the mean might be a deceptive center measure.

Calculating the Mean, Median, and Mode

Mean: Total number of sunglasses / total quantity of pries

Mean = (20 + 20 + 50 + 50 + 50 + 60 + 60 + 60 + 60 + 60 + 60 + 70 + 70 + 70 + 80 + 80 + 80 + 80 + 90 + 90 + 90 + 90 + 100 + 100 + 130) / 25

Mean = 70.8

Median is equal to the (n/2 + 1)th term.

The number of sunglasses in this case is n.

(25/2 + 1)th term as the median

Median = 13th term

Median is 70

Mode is the most frequent data

Therefore, mode = 70

Why is mean the most appropriate central measure ?

The mean is often the ideal measure of central tendency to use when your data distribution is continuous and symmetrical, such as when your data are normally distributed. So, mean here denotes the typical cost of the sunglasses.

Learn more about mean here:

brainly.com/question/17060266

#SPJ1

5 0

2 years ago

If the acceleration of an object is given by dv/dt = −2v, Find the position function s(t) if v(0) = 7 and s(0) = 0.

kirill [66]

Answer:

Step-by-step explanation:

Given that acceleration of an object is

$\frac{dv}{dt} =-2v\\\frac{dv}{v} =-2dt\\ln v = -2t+C\\$

is the solution to the differential equation

Since v(0) =7

we get ln 7 = C

Hence $lnv = -2t+ln 7\\v=7e^{-2t}$

since velocity is rate of change of distance s we have

$v=\frac{ds}{dt} =7e^{-2t}\\s= [tex]s(t) =\frac{-7}{2} (e^{-2t})+C)[$

substitute t=0 and s=0

$C=7/2$

So solution for distance is

$s(t) =\frac{-7}{2} (e^{-2t}-1)$

4 0

3 years ago

Which mixed number is equivalent to the improper fraction below?

Solnce55 [7]

D is the correct fraction

5 0

3 years ago

Car A's fuel efficiency is 34 miles per gallon of gasoline, and car B's fuel efficiency is 23 miles per gallon of gasoline. At t

Verdich [7]

Answer:

22 more gallons.

Step-by-step explanation:

Given:

Car A's fuel efficiency is 34 miles per gallon of gasoline.

Car B's fuel efficiency is 23 miles per gallon of gasoline.

Question asked:

At those rates, how many more gallons of gasoline would car B consume than car A on a 1,564 miles trip?

Solution:

Car A's fuel efficiency is 34 miles per gallon of gasoline.

By unitary method:

Car A can travel 34 miles in = 1 gallon

Car A can travel 1 mile in = $\frac{1}{34} \ gallon$

Car A can travel 1564 miles in = $\frac{1}{34} \times1564=46\ gallons$

Car B's fuel efficiency is 23 miles per gallon of gasoline.

Car B can travel 23 miles in = 1 gallon

Car B can travel 1 mile in = $\frac{1}{23} \ gallon$

Car B can travel 1564 mile in = $\frac{1}{23} \times1564=68\ gallons$

We found that for 1564 miles trip Car A consumes 46 gallons of gasoline while Car B consumes 68 gallons of gasoline that means Car B consumes 68 - 46 = 22 gallons more gasoline than Car A.

Thus, Car B consumes 22 more gallons of gasoline than Car A consumes.

6 0

3 years ago