1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Ksivusya [100]
3 years ago
13

6/15 divided by 1/7

Mathematics
2 answers:
mylen [45]3 years ago
6 0
Question-
6/15 divided by 1/7

Answer-
Find the reciprocal of the divisor
Reciprocal of 1/7: 7/1Now, multiply it with the dividend
So, 6/15 ÷ 1/7 = 6/15 × 7/1= (6 × 7)/(15 × 1) = 42/15After reducing the fraction, the answer is 14/5In mixed form: 2 4/5
Anna71 [15]3 years ago
3 0
The answer is 2/35. 6x1=6 and 15x7=105. Then you have to divide both of them by 3. 
You final answer will be 2/35.
You might be interested in
The image of the point (2, 1) under a translation is (5, -3). Find
Yanka [14]

Answer:

The coordinates of the image of the point (6,6) under the same  translation is: (9, 2)

Hence, option C is correct.

Step-by-step explanation:

The image of the point (2, 1) under a translation is (5, -3).

It means when we horizontally move 3 units to the RIGHT i.e. adding 3 units to the x-coordinate and vertically move 4 units DOWN i.e. subtracting 4 units from the y-coordinate of the original point (2, 1), we get the coordinates of the image (5, -3).

Thus,

The rule of translation can be formulated such as:

(x, y) → (x + 3, y - 4)

(2, 1) → (2 + 3, 1 - 4) → (5, -3)

Thus,

Under the same rule of translation, we can determine the coordinates of the image of the point (6,6):

(x, y) → (x + 3, y - 4)

(6, 6) → (6 + 3, 6 - 4) → (9, 2)

Therefore, the coordinates of the image of the point (6,6) under the same  translation is: (9, 2)

Hence, option C is correct.

4 0
2 years ago
Pls help me this is 7th grade (ADVANCED)
aleksandrvk [35]

Answer:

it  (6,18,23)

Step-by-step explanation:

3 0
2 years ago
I need an answer! NO LINKS PLS! il give brainlist
cricket20 [7]

Answer:

D. The company's chocolate bars weigh 3.2 ounces on average.

Step-by-step explanation:

We are given that  a company claims that its chocolate bars weigh 3.2 ounces on average.

The company took many large samples, and each time the mean weight of the sample was within the 95% confidence interval.

Definition of 95% confidence level: 95% confidence level means a range of values that you can be 95% certain contains the true mean of the population.

Thus by considering definition we can conclude that The company's chocolate bars weigh 3.2 ounces on average.

Thus Option D is correct.

D. The company's chocolate bars weigh 3.2 ounces on average.

4 0
3 years ago
10 POINTS PLEASE HELP ME!!
castortr0y [4]
Vertical angles is the answer

Supplementary means they add up to 180
Adjacent means they are next to each other
Complementary means they add up to 90
So the answer is vertical
6 0
3 years ago
Find the missing length in the image below
Ket [755]

Answer:

1 length ityoughkdds hshlkb

7 0
2 years ago
Read 2 more answers
Other questions:
  • Number 8 please .......
    8·1 answer
  • Nine and one half less than four and one half times a number is greater than 62,5. Which of the following represents
    14·2 answers
  • Sarabeth ran 1 2/5 miles on a path around the park. This was 5/8 of the distance around the park. What is the distance around th
    7·1 answer
  • 0.4 which one is bigger? 0.36
    7·2 answers
  • A department store purchases Which expression shows the
    14·1 answer
  • Write y=-1/4x-6 in standard form using integers.
    5·1 answer
  • A 15-g sample of radioactive iodine decays in such a way that the mass remaining after t days is given by
    12·1 answer
  • Find compound interest on12600rupees for 2years at10% per annum compounded anually<br>​
    11·1 answer
  • Caroline wants to compare the expressions 15-9 and 9 (-15) to determine which result is greater. How can she do this without fin
    10·1 answer
  • ____ : 28 = 42 : 49.
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!