Answer:
Let A1=a1+a2+a3, A2=a2+a3+a4, and so on, A10=a10+a1+a2. Then A1+A2+⋯+A10=3(a1+a2+⋯+a10)=(3)(55)=165, so some Ai≥165/10=16.5, so some Ai≥17.
Step-by-step explanation:
Answer:
help me first on this question
Step-by-step explanation:
Answer:
18.8888888889
Step-by-step explanation:
2 5/6 = 2.83333333333
6 2/3 = 6.66666666667
2 5/6 * 6 2/3 = 2.83333333333 * 6.66666666667
2.83333333333 * 6.66666666667= 18.8888888889
Answer:
Step-by-step explanation:
*There is an acute isosceles (don't know if I am spelling any of these correct)
*Right Scalene
*right isosceles
*equilateral
Those are some of the ones that I found