Initially, Ball A of 10 kg will have velocity x, while Ball B of 30 kg has velocity -10 m/s.
After collision, Ball A will have a velocity of -30 m/s, while Ball B will have velocity 10 m/s. We assume their masses do not change.
(10 kg)(x m/s) + (30 kg)(-10 m/s) = (10 kg)(-30 m/s) + (30 kg)(10 m/s)
10x - 300 = -300 + 300
x = 30 m/s (to the right)
I'm not sure I'm right, I'm not all that good at elimination but I think the answer is y = 13. So I guess the answer would be A. one solution
Answer: (5,18); (-5,38)
Step-by-step explanation:
x^2-2x+3=-2x+28
x^2-25=0
(x-5)(x+5)= 0
-2(5)+28= 18
-2(-5)+28=38
(5,18)(-5,38)
(First equation:Multiply 6•7=42. 42+5=47)=(second equation:7 to the 2nd power is 49. 49-2=47 )
A line graph sounds like the best option
