Expand 5⁴ WHAT IS THE ANSWER

What is the answer to -128=8x ?

Alexandra [31]

1. Do inverse operation
-128 = 8x
8 8
-16 = x

2. Substitute (Optional)
-128 = 8(-16)
-128 = -128

4 0

3 years ago

Read 2 more answers

What is the transformation that occurs to the equation y=2^x if it changes to y=2^x +5

Crank

It moves either 5 to the right or 5 up, but i'm pretty sure it's 5 to the right.

5 0

3 years ago

Which of the following inequalities have no solution over all real numbers? Check all that apply.

Likurg_2 [28]

Answer:

cos(x)<-2

-1<csc(x)<1

cos(x)-1>.5

Step-by-step explanation:

I just answered this question and got these answers.

7 0

4 years ago

[Q71 Suppose that the height, in inches, of a 25-year-old man is a normal random variable with parameters g = 71 inch and 02 = 6

viktelen [127]

Answer: (a) Percentage of 25 year old men that are above 6 feet 2 inches is 11.5%.

(b) Percentage of 25 year old men in the 6 footer club that are above 6 feet 5 inches are 2.4%.

Step-by-step explanation:

Given that,

Height (in inches) of a 25 year old man is a normal random variable with mean $g=71$ and variance $o^{2} =6.25$ .

To find: (a) What percentage of 25 year old men are 6 feet, 2 inches tall

(b) What percentage of 25 year old men in the 6 footer club are over 6 feet. 5 inches.

Now,

(a) To calculate the percentage of men, we have to calculate the probability

P[Height of a 25 year old man is over 6 feet 2 inches]= P[X> $74in$ ]

P[X>74] = P[ $\frac{X-g}{o}$ > $\frac{74-71}{2.5}$ ]

= P[Z > 1.2]

= 1 - P[Z ≤ 1.2]

= 1 - Ф (1.2)

= 1 - 0.8849

= 0.1151

Thus, percentage of 25 year old men that are above 6 feet 2 inches is 11.5%.

(b) P[Height of 25 year old man is above 6 feet 5 inches gives that he is above 6 feet] = P[X, $6ft$ $5in$ - X, $6ft$ ]

P[X > $6ft$ $5in$ I X > $6ft$ ] = P[X > 77 I X > 72]

= $\frac{P[X > 77]}{P[ X > 72]}$

= $\frac{P[\frac{X - g}{o}>\frac{77-71}{2.5}] }{P[\frac{X-g}{o} >\frac{72-71}{2.5}] }$

= $\frac{P[Z >2.4]}{P[Z>0.4]}$

= $\frac{1-P[Z\leq2.4] }{1-P[Z\leq0.4] }$

= $\frac{1-0.9918}{1-0.6554}$

= $\frac{0.0082}{0.3446}$

= 0.024

Thus, Percentage of 25 year old men in the 6 footer club that are above 6 feet 5 inches are 2.4%.

4 0

4 years ago

An industry demand curve faced by firms in a duopoly is P = 69 - Q, where Q = Q1 + Q2. MC for each firm is 0. How many units sho

emmasim [6.3K]

You first need to establish the benefits function B. For each firm it is equal to the amount produced (q1 for firm 1 and q2 for firm 2) multiplied by the price P, minus cost C. It is

B1 = P.q1 - C1 = (69 - q1 - q2)q1 - C1

B2= P.q2 - C2 = (69 - q1 - q2)q2 - C2

As firma Will maximize benefits we need the derivative in q1 and q2 for firms 1 and 2 respectively. This will give us

69 - 2q1 - q2 = 0

69 - q1 - 2q2 = 0

Note that the derivative of cost is null as marginal cost is null.

Thus,

q2= 69 - 2q1

Replacing on the second equation:

69- q1 - 138 + 4q1 = 0

-69 + 3q1= 0

q1= 69/3=23

Replacing in the q2 equation:

q2=69- 46= 23

To find the money they make replace in benefits function. First we find piece P=69-23-23=23. Thus:

B1=23*23-C1

B2=23*23-C2

As we don't have a value for C1 and C2 we can't compute a number for benefits. If you have these values you will have the benefits.

7 0

4 years ago

Expand 5⁴ WHAT IS THE ANSWER​

Expand 5⁴ WHAT IS THE ANSWER