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katrin2010 [14]
3 years ago
15

A motorcycle starts from rest . If its gain an acceleration of 2m/s^2 in 5 second , Calculate the final velocity.

Mathematics
2 answers:
iren [92.7K]3 years ago
5 0

Answer:

u=0m/s

v=?

a=2m/s^2

t=5s

v=u+at

v=0+2*5

v=10m/s

densk [106]3 years ago
4 0
  • initial velocity=u=0m/s
  • Acceleration=a=2m/s^2
  • Time=t=5s
  • Final velocity=v=?

Using first equation of kinematics

\\ \sf\longmapsto v=u+at

\\ \sf\longmapsto v=0+2(5)

\\ \sf\longmapsto v=10m/s

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Help pls with answer!!!Rewrite the function in the given form.
Elis [28]

Answer:

g(x) = \frac{-2}{x-1}+5\\\\

The graph is shown below.

=========================================================

Explanation:

Notice that if we multiplied the denominator (x-1) by 5, then we get 5(x-1) = 5x-5.

This is close to 5x-7, except we're off by 2 units.

In other words,

5x-7 = (5x-5)-2

since -7 = -5-2

Based on that, we can then say,

g(x) = \frac{5x-7}{x-1}\\\\g(x) = \frac{5x-5-2}{x-1}\\\\g(x) = \frac{(5x-5)-2}{x-1}\\\\g(x) = \frac{5(x-1)-2}{x-1}\\\\g(x) = \frac{5(x-1)}{x-1}+\frac{-2}{x-1}\\\\g(x) = 5+\frac{-2}{x-1}\\\\g(x) = \frac{-2}{x-1}+5

This answer can be reached through alternative methods of polynomial long division or synthetic division (two related yet slightly different methods).

-------------------------

Compare the equation g(x) = \frac{-2}{x-1}+5\\\\ to the form g(x) = \frac{a}{x-h}+k\\\\

We can see that

  • a = -2
  • h = 1
  • k = 5

The vertical asymptote is x = 1, which is directly from the h = 1 value. If we tried plugging x = 1 into g(x), then we'll get a division by zero error. So this is why the vertical asymptote is located here.

The horizontal asymptote is y = 5, which is directly tied to the k = 5 value. As x gets infinitely large, then y = g(x) slowly approaches y = 5. We never actually arrive to this exact y value. Try plugging in g(x) = 5 and solving for x. You'll find that no solution for x exists.

The point (h,k) is the intersection of the horizontal and vertical asymptote. It's effectively the "center" of the hyperbola, so to speak.

The graph is shown below. Some points of interest on the hyperbola are

  • (-1,6)
  • (0,7) .... y intercept
  • (1.4, 0) .... x intercept
  • (2, 3)
  • (3, 4)

Another thing to notice is that this function is always increasing. This means as we move from left to right, the function curve goes uphill.

7 0
3 years ago
Adam is 9 years old and Billy is 11 years old. What will be the ratio of Adams’ age to Billy’s age in exactly one year’s time? G
son4ous [18]

Answer:

10 / 12

simplified:

5/6

since 5 is a prime number, we can't simplify this ratio any further

4 0
3 years ago
Please help! Been stuck on this for hours Solve the inequality. Express your answer in interval form. (If there is no solution,
yawa3891 [41]

Answer:

  (-√8, -√6] ∪ [-√2, 0) ∪ (0, √2] ∪ [√6, √8)

Step-by-step explanation:

The inequality resolves into 4 inequalities. There are 4 intervals in the solution.

Starting at the left, for the absolute value argument less than 0:

  2 ≤ -(x^2 -4) . . . . . . . for x^2 -4 ≤ 0

  2 ≤ -x^2 +4

  -2 ≤ -x^2

  2 ≥ x^2 . . . . . . . . . . consistent with the above 4 ≥ x^2

  -√2 ≤ x ≤ √2 . . . . . square root; may be limited by other constraints

For the absolute value argument greater than 0:

  2 ≤ x^2 -4 . . . . . . . for x^2 -4 ≥ 0

  6 ≤ x^2 . . . . . . . . . .consistent with x^2 ≥ 4

  -√6 ≥ x ∪ x ≤ √6 . . . . take the square root

__

The inequality on the right can be written as the compound inequality ...

  -4 < x^2 -4 < 4

  0 < x^2 < 8 . . . . . add 4

  0 < |x| < √8 . . . . take the square root

This resolves to ...

  -√8 < x < 0 ∪ 0 < x < √8

__

So, the solution set is the set of values of x that satisfy these restrictions on x:

  -√2 ≤ x ≤ √2

  x ≤ -√6 ∪ x ≤ √6

  -√8 < x < 0 ∪ 0 < x < √8

That is a collection of 4 intervals:

  (-√8, -√6] ∪ [-√2, 0) ∪ (0, √2] ∪ [√6, √8)

_____

You may be expected to write √8 as 2√2.

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These intervals are the portions of the red curve that lie between the two horizontal lines. The points on the upper (dashed) line are not part of the solution set. The points on the lower (solid) line are part of the solution set.

7 0
3 years ago
a rectangular lawn has an area of a^3 - 125. use the difference of cubes to find out the dimensions of the rectangle.
ANEK [815]

The area of a rectangle is the product of its dimensions

The dimensions of the rectangle are: \mathbf{Length = a -5} and \mathbf{Width = a^2 + 5a + 25}

The area is given as:

\mathbf{Area = a^3 - 125}

Express 125 as 5^3

\mathbf{Area = a^3 - 5^3}

Apply difference of cubes

\mathbf{Area = (a - 5)(a^2 + 5a + 5^2)}

\mathbf{Area = (a - 5)(a^2 + 5a + 25)}

The area of a rectangle is:

\mathbf{Area = Length \times Width}

So, by comparison:

\mathbf{Length = a -5}

\mathbf{Width = a^2 + 5a + 25}

Read more about areas at:

brainly.com/question/3518080

6 0
2 years ago
Identify the constant of proportionality from the graph. 11 10 9 00 7 6 5 1 2 3 4 5 6 7 8 9 10 11 O A. 4 B. 8 O c. D. 3​
mafiozo [28]

Answer:

A. 4

Step-by-step explanation:

Constant of proportionality (k) = y/x

We can use the coordinates of any point on the line to find k.

Let's use (2, 8)

Constant of proportionality (k) = 8/2

Constant of proportionality (k) = 4

4 0
3 years ago
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