Answer:
The probability of Jessica picking 3 consecutive red markers is: (1/6)
The probability of Jessica's first marker being red, but not picking 3 consecutive red markers is:
(3/5)−(1/6)=(13/30)
So i am bit stuck here
what i think is it shouldn't be that complex it should be as simple as chance of Jessica's first marker being red=chance of getting red 1 time i.e P(First marker being red)=(6/10) can any explain me the probability of Jessica's first marker being red=(13/30)?
Step-by-step explanation:
Answer: 2/5
Step-by-step explanation:
Answer:
64a³c²⁷
Step-by-step explanation:
The expression inside parentheses can be simplified by noting that b^0 = 1. Then you have ...
(4ac^9)^3
The rules of exponents say the exponent outside applies to each of the inside factors. For c^9, the exponents multiply.
Here are the applicable rules:
(ab)^c = (a^c)(b^c)
(a^b)^c = a^(b·c)
__
(4ac^9)^3 = 4^3·a^3·c^(9·3) = 64a^3c^27
Answer:
Step-by-step explanation:
9/10= 0,9
4/5= 0,8
13/15= 0,86
16/25= 0,64
