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2 years ago

Solve the equation x=24 √468 ÷18

Mathematics

1 answer:

sattari [20]2 years ago

7 0

Answer:

x = 8√13 ≈ 28.8444

Step-by-step explanation:

It looks like you want to evaluate ...

$\dfrac{24\sqrt{468}}{18}=\dfrac{4\sqrt{6^2\cdot 13}}{3}\\\\=\dfrac{4\cdot 6\sqrt{13}}{3}=8\sqrt{13}$

Your calculator can tell you the value of this. It is approximately 28.8444.

You might be interested in

The value of y varies jointly with the values of x and z When x = 4 and z = 10, the value of y is 360.

Igoryamba

Answer:

Step-by-step explanation:

Joint variation is given by:

$y=kxz$

Where k is some constant.

We are given that y = 360 when x = 4 and z = 10. Therefore:

$360=k(4)(10)$

Solving for k:

$40k=360\Rightarrow k=9$

Therefore, our equation is:

$y=9xz$

Then when x = 5 and z = 12:

$y=9(5)(12)=540$

The answer is A.

3 0

3 years ago

the marks in an examination for a Physics paper have normal distribution with mean μ and variance σ2 . 10% of the students obtai

Blababa [14]

Let $X$ be the random variable for the number of marks a given student receives on the exam.

10% of students obtain more than 75 marks, so

$P(X>75)=P\left(\dfrac{X-\mu}\sigma>\dfrac{75-\mu}\sigma\right)=P(Z>z_1)=0.10$

where $Z$ follows a standard normal distribution. The critical value for an upper-tail probability of 10% is

$P(Z>z_1)=1-F_Z(z_1)=0.10\implies z_1=F_Z^{-1}(0.90)$

where $F_Z(z)=P(Z\le z)$ denotes the CDF of $Z$ , and $F_Z^{-1}$ denotes the inverse CDF. We have

$z_1=F_Z^{-1}(0.90)\approx1.2816$

Similarly, because 20% of students obtain less than 40 marks, we have

$P(X$

so that

$P(Z$

Then $\mu,\sigma$ are such that

$\dfrac{75-\mu}\sigma\approx1.2816\implies75\approx\mu+1.2816\sigma$

$\dfrac{40-\mu}\sigma\approx-0.8416\implies40\approx\mu-0.8416\sigma$

and we find

$\mu\approx53.8739,\sigma\approx16.4848$

3 0

3 years ago

For what values of $x$ is it true that $x^2 - 5x - 4 \le 10$? Express your answer in interval notation.

dybincka [34]

Answer:

x ∈ [-2, 7]

Step-by-step explanation:

The given equation ...

x^2 -5x -4 ≤ 10

can be rewritten as ...

x^2 -5x -14 ≤ 0

and factored as ...

(x +2)(x -7) ≤ 0

Clearly, the "or equal to" condition will be met when x=-2 and x=7. For values of x between these numbers, one factor is negative and the other is positive. Hence the product will be negative. So, numbers in that interval are the solution set.

x ∈ [-2, 7]

5 0

2 years ago

Billy says that he can add 23 and 40 without regrouping is Bill correct how do you know

bija089 [108]

Yes he is correct because if you do the algorithm, 0+3=3 and 20+40=60 and 60+3=63. There is no regrouping needed.

6 0

2 years ago

21. Brian wants to purchase a piece of fabric

ella [17]

Brian should purchase Choice C of fabric

<em><u>Solution:</u></em>

Given that Brian wants to purchase a piece of fabric that is between 49 and 53 inches long

So piece of fabric should be between: 49 and 53 inches

Choice A is $4\frac{3}{4}$ feet long

Let us convert feet to inches

$4\frac{3}{4} feet = \frac{4 \times 4 + 3}{4} = \frac{19}{4} feet$

Now convert to inches

We know that,

1 feet = 12 inches

$\frac{19}{4} feet = \frac{19}{4} \times 12 = 57 inches$

But this choice is greater than given condition that piece of fabric should be between: 49 and 53 inches

So this is not correct

Choice B is $4\frac{1}{2}$ feet long

$4\frac{1}{2} feet = \frac{2 \times 4 + 1}{2} = \frac{9}{2} feet$

Now convert to inches

$\frac{9}{2} feet = \frac{9}{2} \times 12 inches = 54 inches$

But this choice is greater than given condition that piece of fabric should be between: 49 and 53 inches

So this is not correct

Choice C is $4\frac{1}{3}$ feet long

$4\frac{1}{3} feet = \frac{3 \times 4 + 1}{3} = \frac{13}{3} feet$

Now convert to inches

$\frac{13}{3} feet = \frac{13}{3} \times 12 inches = 52 inches$

So this 52 inches lies between 49 and 53 inches

So Brian should purchase Choice C of fabric

8 0

3 years ago