We have been given that Judy’s brother Sam has a collection of 96 comic books.
We have been asked to find the 10 ways Sam could divide his comic books into equal groups.
This can be done as follows:
96 can be written as .
Thus, we can either have 2 groups of 48 comics or 48 groups of 2 comics. As we can see we have 2 ways to divide the comic books in equal groups.
Likewise, 96 can also be written as . Here, we can similarly see that we can either have 3 groups of 32 comics or 32 groups of 3 comics. As we can again see we have 2 more ways to divide the comic books in equal groups, taking the total number of ways to 4.
Continuing in this manner we will see that we can have 4 groups of 24 or 24 groups of 4, 6 groups of 16 or 16 groups of 6 and lastly 12 groups of 8 or 8 groups of 12 comic books, thus taking the count to a total of 10 ways in which Sam can divide his comic books into equal groups.
Answer:
8 times
Step-by-step explanation:
3/4 n = 6
Multiply each side by 4/3 to isolate n
4/3 * 3/4 n = 6*4/3
n = 8
The sum means addition.
Add the like terms together.
4x^3+2x^2-4x+3
+ 7x^3-4x^2+7x+8
4x^3 + 7x^3 = 11x^3
2x^2 + -4x^2 = -2x^2
-4x +7x = 3x
3 +8 = 11
The answer is : 11x^3 - 2x^2 + 3x + 11
Step-by-step explanation:
let width be x
length = 6+x
x times 6+x=135
2x+6=135
2x=135-6
129/2=x
64.5
Answer:
11 Square Units
Step-by-step explanation:
Let A be the area of the Rectangle
First statement: The area of the rectangle is increased by seven, we have :
A+7
Second Statement: Four less than twice the area of the rectangle
Twice the Area=2A
Four less = 2A-4
Therefore:
2A-4=A+7
Collecting like terms
2A-A =7+4
A=11
The area of the rectangle is 11 Square Units.
