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Korolek [52]
3 years ago
6

Jala put $600 in an interest bearing account with a annual compound interest rate of 5%. Jala determined that after seven years,

she will have a total balance of $844.26. Using the rule of 72, t+72/t how many more years will it be before Jala’s $600 doubles in value? Round to the nearest tenth.
3.3 years
7.4 years
10.3 years
14.4 years
Mathematics
2 answers:
tiny-mole [99]3 years ago
8 0

Answer:

C

Step-by-step explanation:

maxonik [38]3 years ago
6 0

Answer:

c

Step-by-step explanation:

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The short sides of a rectangle are 2 inches. The long sides of the same rectangle are three less than an unknown number of inche
mash [69]

Answer:

6,4

Step-by-step explanation:

I'm not sure if 4 is correct but 6 definitely is. I hope this helps

3 0
2 years ago
+ PLEASE ANSWER+ In order to inscribe a square in a circle using only a compass and a straight edge, you must first draw a _____
faust18 [17]

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Radius

Step-by-step explanation:

7 0
3 years ago
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Use the distributive property then combine any like terms<br><br> 4(7p+4-2p)
ivolga24 [154]

Answer:20p+16

Step-by-step explanation:

Combine like terms

4(7p+4-2p)

4(5p+4)

Distribute

4(5p+4)

20p+16

7 0
3 years ago
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You have an ant farm with 35 ants. The population of ants in your farm will double every 3 months. The table shows the populatio
vfiekz [6]

Answer:

560 ants and non linear function

Step-by-step explanation:

12 months divided by 3 months is 4. 35 times 2 is 70. Again is 140. Again is 280. Again a 4th time is 560 ants. It is not linear because it does not increase the same amount each time.

7 0
2 years ago
For the polynomial function ƒ(x) = −x6 + 3x4 + 4x2, find the zeros. Then determine the multiplicity at each zero and state wheth
murzikaleks [220]

There is a multiple zero at 0 (which means that it touches there), and there are single zeros at -2 and 2 (which means that they cross). There is also 2 imaginary zeros at i and -i.


You can find this by factoring. Start by pulling out the greatest common factor, which in this case is -x^2.


-x^6 + 3x^4 + 4x^2

-x^2(x^4 - 3x^2 - 4)


Now we can factor the inside of the parenthesis. You do this by finding factors of the last number that add up to the middle number.


-x^2(x^4 - 3x^2 - 4)

-x^2(x^2 - 4)(x^2 + 1)


Now we can use the factors of two perfect squares rule to factor the middle parenthesis.


-x^2(x^2 - 4)(x^2 + 1)

-x^2(x - 2)(x + 2)(x^2 + 1)


We would also want to split the term in the front.


-x^2(x - 2)(x + 2)(x^2 + 1)

(x)(-x)(x - 2)(x + 2)(x^2 + 1)


Now we would set each portion equal to 0 and solve.


First root

x = 0 ---> no work needed


Second root

-x = 0 ---> divide by -1

x = 0


Third root

x - 2 = 0

x = 2


Forth root

x + 2 = 0

x = -2


Fifth and Sixth roots

x^2 + 1 = 0

x^2 = -1

x = +/- \sqrt{-1}

x = +/- i

7 0
3 years ago
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