For there to be 1 car, we consider two possible outcomes:
The first door opened has a car or the second door opened has a car.
P(1 car) = 2/6 x 4/5 + 4/6 x 2/5
P(1 car) = 8/15
For there to be no car in either door
P(no car) = 4/6 x 3/5
P(no car) = 2/5
Probability of at least one car is the sum of the probability of one car and probability of two cars:
P(2 cars) = 2/6 x 1/5
= 1/15
P(1 car) + P(2 cars) = 8/15 + 1/15
= 3/5
Answer:
The answer is 3.65 x 10^3 power.
Step-by-step explanation:
In scientific notation, you need only the one's place, so 36.5 would not work. I hope this helps, I know this is a day late and you probably figured it out, but just in case you didn't, here is the answer :)
Yes with a <span>58,016 Square Kilometers</span>
Answer:
see below
Step-by-step explanation:
The steps are +2 then *4 then -8 then ÷2
Input is 5
5 +2 =7 *4 = 28-8 = 20 ÷2 = 10 Output is 10
Input is 9
9 +2 =11 *4 = 44-8 = 36 ÷2 = 18 Output is 18
Input is 14
14 +2 =16 *4 = 64-8 = 56 ÷2 = 28 Output is 28
Input is 18
18 +2 =20 *4 = 80-8 = 72 ÷2 = 36 Output is 36
Input is 23
23 +2 =25 *4 = 100-8 = 92 ÷2 = 46 Output is 46
Input is 7.5
7.5 +2 =9.5 *4 = 38-8 = 30 ÷2 = 20 Output is 20
Input is 11.54
11.54 +2 =13.54 *4 = 54.16-8 = 46.16 ÷2 = 23.08 Output is 23.08
Answer:
that would be the third one
Step-by-step explanation: