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ELEN [110]
2 years ago
5

Sixty- five percent of men consider themselves knowledgeable football fans.

Mathematics
1 answer:
Rama09 [41]2 years ago
6 0

Answer: d) 0.238

Step-by-step explanation:

We would assume binomial distribution for the number of men sampled. The formula for binomial distribution is expressed as

P(x =r) = nCr × q^(n - r) × p^r

Where

p represents the probability of success.

q represents the probability of failure.

n represents the number of samples.

From the information given,

n = 10

p = 65% = 65/100 = 0.65

q = 1 - p = 1 - 0.65 = 0.35

The probability that exactly six of them will consider themselves knowledgeable fans is expressed as P(x = 6). It becomes

P(x =6) = 10C6 × 0.35^(10 - 6) × 0.65^6

P(x =6) = 10C6 × 0.35^4 × 0.65^6

P(x =6) = 0.238

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Between 0 degrees Celsius and 30 degrees Celsius, the volume V (in cubic centimeters) of 1 kg of water at a temperature T is giv
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Answer:

T = 3.967 C

Step-by-step explanation:

Density = mass / volume

Use the mass = 1kg and volume as the equation given V, we will come up with the following equation

D = 1 / 999.87−0.06426T+0.0085043T^2−0.0000679T^3

   = (999.87−0.06426T+0.0085043T^2−0.0000679T^3)^-1

Find the first derivative of D with respect to temperature T

dD/dT = \dfrac{70000000\left(291T^2-24298T+91800\right)}{\left(679T^3-85043T^2+642600T-9998700000\right)^2}

Let dD/dT = 0 to find the critical value we will get

\dfrac{70000000\left(291T^2-24298T+91800\right)}  = 0

Using formula of quadratic, we get the roots:

T =  79.53 and T = 3.967

Since the temperature is only between 0 and 30, pick T = 3.967

Find 2nd derivative to check whether the equation will have maximum value:

-\dfrac{140000000\left(395178T^4-65993368T^3+3286558821T^2+2886200857800T-121415215620000\right)}{\left(679T^3-85043T^2+642600T-9998700000\right)^3}

Substituting the value with T=3.967,

d2D/dT2 = -1.54 x 10^(-8)    a negative value. Hence It is a maximum value

Substitute T =3.967 into equation V, we get V = 0.001 i.e. the volume when the the density is the highest is at 0.001 m3 with density of

D = 1/0.001 = 1000 kg/m3

Therefore T = 3.967 C

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3 years ago
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A. The tree starts at 0 and increases by 1 every year. The height starts at 5 and increases by 1 every year.

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Step-by-step explanation:

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To solve this problem, we have to use the area of both gauze or the dimensions on each gauze and compare them. we can see that the sheets are not similar as they have different areas.

<h3>Area of Rectangle</h3>

The area of a rectangle is given as the product between the length and it's width.

Data;

  • Length = 9in
  • Area = 45in^2
  • width = ?
  • length 2 = 4in
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area = length * width

In the first gauze, the area is given as 45in^2 and we have value of the length. To find the width of the first gauze can be calculated as

A = length * width\\width = \frac{area}{length} \\width = \frac{45}{9} \\width = 5in

We can see that the width are not equal so is their length.

But if we would truly compare them, the accurate way to do that is by their area

The area of the second gauze is given by

a = 3 * 4 = 12in^2

From the above calculations, we can see that the sheets are not similar as they have different areas.

Learn more on area of a rectangle here;

brainly.com/question/25292087

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