Mode = number which appears the most
The mode for your question is 5
Answer:
If A(t) represents the amount of salt in the tank at time t, the correct differential equation for A is is dA/dt = 15 - 0.005A
Option C) dA/dt = 15 - 0.005A is the correction Answer
Step-by-step explanation:
Given the data in the question;
If A(t) represents the amount of salt in the tank at time t, the correct differential equation for A is?
dA/dt = rate in - rate out
first we determine the rate in and rate out;
rate in = 3pound/gallon × 5gallons/min = 15 pound/min
rate out = A pounds/1000gallons × 5gallons/min = 5Ag/1000pounds/min
= 0.005A pounds/min
so we substitute
dA/dt = rate in - rate out
dA/dt = 15 - 0.005A
Therefore, If A(t) represents the amount of salt in the tank at time t, the correct differential equation for A is is dA/dt = 15 - 0.005A
Option C) dA/dt = 15 - 0.005A is the correction Answer
62%
of 25
'of' means multiplication.
![\sf 62\%\times 25](https://tex.z-dn.net/?f=%5Csf%2062%5C%25%5Ctimes%2025)
Convert 62% to a decimal, divide it by 100(since percentages are parts of 100):
62/100 = 0.62
![\sf 0.62\times 25](https://tex.z-dn.net/?f=%5Csf%200.62%5Ctimes%2025)
Multiply:
The number of combinations of the 8 candidates taken 4 at a time is: