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aleksandrvk [35]
2 years ago
8

Find the ranges giving brainlest

Mathematics
1 answer:
scoray [572]2 years ago
5 0

Answer:

The range for Problem 18 is

16.1

The range for problem 19 is

167

Step-by-step explanation:

To find the range you subtract the smallest value from the largest value. In problem 18 the largest value was 17.6 and the smallest was 1.5.

17.6 - 1.5 = 16.1

In problem 19 the largest value was 181 and the smallest was 14

181 - 14 = 167

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Which simplified fraction is equal to 0.53 with bar?
Oxana [17]

I assume that 0.53 with a bar means the decimal fraction in which 3 is repeating.

24/45, 8/15, and 48/90 all result in the same decimal value. Thus, we are simply looking for the one that is fully simplified.

The correct answer is 8/15.

Hope this helps!

5 0
2 years ago
Classify the following triangle. Check all that apply
lubasha [3.4K]

Answer:

A. Acute and B. Equilateral

Step-by-step explanation:

8 0
2 years ago
Find the x intercept. (Using the equation is more accurate, but I included a graph for reference)
MariettaO [177]
For the X intercept you set y = 0 and solve for x

Y = - \frac{8}{3}x + 9
0= - \frac{8}{3}x + 9 subtract 9 from both sides
-9 = -\frac{8}{3} x divide both sides by 3
-3 = -8x  divide both sides by -8
\frac{3}{8} = x

X-intercept = (\frac{3}{8}, 0)
4 0
3 years ago
Pls help if you only know the correct answer! Thanks! :)
FromTheMoon [43]
Yes yes yes yes yes yes yes that is the makers Ik the answer it’s easy do you need help if so tell me
3 0
2 years ago
Someone help me with this
Jet001 [13]

2a. 14,9; 2b. 15,4; 2c. 30,8; 3. 32

For 2a., you have to set it up like this: csc 48° = 20⁄x [OR sin 48° = ˣ⁄20]. Then you would have to isolate the variable by getting rid of the denominator. The cosecant function has an extra step because you will get xcsc 48° = 20. As stated, isolate the variable; this time, divide by csc 48°. This is what 20 will be divided by to get your x, whereas the other side cancels out. Then you have to round to the nearest tenth degree.

For 2b., you have to set it up like this: sec 39° = ˣ⁄12 [OR cos 39° = 12⁄x. Then you would have to isolate the variable by getting rid of the denominator. The cosine function has an extra step because you will get xcos 39° = 12. As stated, isolate the variable; this time, divide by cos 39°. This is what 12 will be divided by to get your x, whereas the other side cancels out. Then you have to round to the nearest tenth degree.

For 2c., you have to set it up like this: cot 64° = 15⁄x [OR tan 64° = ˣ⁄15]. Then you would have to isolate the variable by getting rid of the denominator. The cotangent function has an extra step because you will get xcot 64° = 15. As stated, isolate the variable; this time, divide by cot 64°. This is what 15 will be divided by to get your x, whereas the other side cancels out. Then you have to round to the nearest tenth degree.

Now, for 3., it is unique, but similar concept. In this exercise, we are solving for an angle measure, so we have to use inverse trigonometric ratios. So, we set it up like this: cot⁻¹ 1⅗ = m<x [OR tan⁻¹ ⅝ = m<x]. We simply input this into our calculator and we get 32,00538321°. When rounded to the nearest degree, we get 32°.

WARNING: If you use a graphing calculator, you have to input it uniquely because most graphing calculators do not have the inverse trigonometric ratios programmed in their systems. This is how you would write this: tan⁻¹ 1⅗⁻¹. You set 1⅗ to the negative first power, ALONG WITH the inverse tangent function, because without it, your answer will be thrown off. Since Cotangent and Tangent are multiplicative inverses of each other, that is the reason why the negative first power is applied ALONG WITH the inverse tangent function.

**NOTE: 1⅗ = 8⁄5

Take into consideration:

sin <em>θ</em> = O\H

cos <em>θ</em><em> </em>=<em> </em>A\H

tan <em>θ</em><em> </em>= O\A

sec <em>θ</em><em> </em>= H\A

csc <em>θ</em><em> </em>= H\O

cot <em>θ</em><em> </em>= A\O

I hope this helps you out alot, but if you are still in need of assistance, do not hesitate to let me know and subscribe to my channel [username: MATHEMATICS WIZARD], and as always, I am joyous to assist anyone at any time.

7 0
3 years ago
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