From the moment the friend passes the bicyclist, his friend covers a distance over time t of (3.63 m/s)*t.
The bicyclist covers a distance of 1/2*(2.11 m/s^2)*t^2. They meet when these distances are equal:
3.63 t = 1.055 t^2 ==> 1.055 t^2 - 3.63 t = 0
==> t = 0 s or t = 3.44 s
Answer:
2
Step-by-step explanation:
First thing you gotta do is find the common denominator.
Do this by listing factors of the denominators:
5- 5, 10, 15, 20, 25, 30
6- 6, 12, 18, 24, 30, 36
5 and 6 both have 30 in common so that's the new denominator for all 3 of the terms.
What you do to the bottom you must do to the top.
Since you multiply 5 by 6 to get 30, you must multiply 2 and 4 by 6 as well.
Since you multiply 6 by 5 to get 30, then multiply 5 by 5 as well.
The new equation is:
+
+
=
Now add the numerators together
The solution is
. Now simplify. 61 is prime, so you cannot change the fraction How many times does 30 go into 61? Two times. This gives us 2
.
It looks correct to me :)
12 x 6s - 8 x 4s = 72s - 32s = 40s
I want to say the answer is A i caulated it and i end up getting 17