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Brums [2.3K]
2 years ago
8

Solve. 4. Find the value of x in the diagram at the right.

Mathematics
1 answer:
nadya68 [22]2 years ago
5 0
The expression is consistent witch means and can keep going a long time the answer is x0x0
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The midpoint of CD is M=(1, 2). One endpoint is C = (6, -2).
Zina [86]

Answer: Endpoint = (-4,6)

Step-by-step explanation:

To find any endpoint use the formula \frac{x_1+x_2}{2} = Xmp    \frac{y_1+y_2}{2} =Ymp

\frac{6+x_2}{2} = 1          \frac{-2+y_2}{2} =2    

multiply each by 2  to simplify

\frac{6+x_2}{2*2} = 1*2 = {6+x_2}= 2    \frac{-2+y_2}{2*2} =2*2 = -2+y_2=4 take the equations and simplify

6+x_{2} = 2                          -2+y_{2} = 4  =  

-6       -6                          +2       +2

   x_{2} = -4                               y_{2} =  6

To check use the Midpoint formula

\frac{-4+6}{2} , \frac{6-2}{2}  = \frac{2}{2} , \frac{4}{2}  = (1,2)

8 0
3 years ago
Two sides of a four sided figure have negative slopes which are the endpoints of the sides of this figure
Dima020 [189]
Hope this helps you.

8 1
3 years ago
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A 4-pound bag of apples costs $5.00. Based on that rate, which equation shows how y, the cost in dollars, is realted to x, the w
makvit [3.9K]
Hey there!

The answer would be B. y = 1.25x

If each pound is $1.25 and you get 4 pounds then that would equal to $5.00 or y.


Hope this helps !
4 0
3 years ago
What is 0.06 divided by 0.5334
Serga [27]
The answer is 0.11248593
5 0
3 years ago
Read 2 more answers
​Joe's annual income has been increasing each year by the same dollar amount. The first year his income was ​$17 comma 90017,900
Vedmedyk [2.9K]

Answer:

In 17th year, his income was $30,700.

Step-by-step explanation:

It is given that the income has been increasing each year by the same dollar amount. It means it is linear function.

Income in first year = $17,900

Income in 4th year = $20,300

Let y be the income at x year.

It means the line passes through the point (1,17900) and (4,20300).

If a line passes through two points (x_1,y_1) and (x_2,y_2), then the equation of line is

y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1)

The equation of line is

y-17900=\frac{20300-17900}{4-1}(x-1)

y-17900=\frac{2400}{3}(x-1)

y-17900=800(x-1)

y-17900=800x-800

Add 17900 on both sides.

y=800x-800+17900

y=800x+17100

The income equation is y=800x+17100.

Substitute y=30,700 in the above equation.

30700=800x+17100

Subtract 17100 from both sides.

30700-17100=800x

13600=800x

Divide both sides by 800.

\frac{13600}{800}=x

17=x

Therefore, in 17th year his income was $30,700.

5 0
3 years ago
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