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Alona [7]
3 years ago
10

Slope is -1/2 and y-intercept is -2

Mathematics
1 answer:
miskamm [114]3 years ago
3 0
Y= -1/2x-2
this is the y=mx+b equation of a line.
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Help please!!!!;;;;;;;;;;;;;;;;;;;;
kozerog [31]

Hey!

-----------------------------------------------

Solution:

= (-18) - (4)

= -18 - 4

= -22

When you subtract a positive to a negative number the end result will always be negative.

-----------------------------------------------

Answer:

B. 22

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Hope This Helped! Good Luck!

3 0
3 years ago
Helppppppppppppp meeee plsssssss.
maria [59]

Answer:

C

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
1. How many fifties are there in one hundred thousand?​
VladimirAG [237]
There are 2,000 fifties in one hundred thousand
7 0
2 years ago
Guys look at the pic of the park and read the question I need this ASAP WITH ALL STEPS the choices are
Alik [6]

Answer:

A. 821.5 Square Yards

Step-by-step explanation:

30 x 30= 900

900 is the area for the whole park

To find the pool area you need to do pi times Radius squared

so 3.14 x 5 x 5

That equals 78.5 for the pool area.

So to find the grass area you need to subtract the pool area from the park

900 - 78.5 = 821.5 square yards!

5 0
3 years ago
The height H of an ball that is thrown straight upward from an initial position 3 feet off the ground with initial velocity of 9
mariarad [96]

Answer:

The ball will be 84 feet above the ground 1.125 seconds and 4.5 seconds after launch.

Step-by-step explanation:

Statement is incorrect. Correct form is presented below:

<em>The height </em>h(t)<em> of an ball that is thrown straight upward from an initial position 3 feet off the ground with initial velocity of 90 feet per second is given by equation </em>h(t) = 3 +90\cdot t -16\cdot t^{2}<em>, where </em>t<em> is time in seconds. After how many seconds will the ball be 84 feet above the ground. </em>

We equalize the kinematic formula to 84 feet and solve the resulting second-order polynomial by Quadratic Formula to determine the instants associated with such height:

3+90\cdot t -16\cdot t^{2} = 84

16\cdot t^{2}-90\cdot t +81 = 0 (1)

By Quadratic Formula:

t_{1,2} = \frac{90\pm \sqrt{(-90)^{2}-4\cdot (16)\cdot (81)}}{2\cdot (16)}

t_{1} = 4.5\,s, t_{2} = 1.125\,s

The ball will be 84 feet above the ground 1.125 seconds and 4.5 seconds after launch.

3 0
3 years ago
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