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wel
3 years ago
14

What is the equation, in standard form, of a circle with center (−5, −9) and radius 7?

Mathematics
1 answer:
dimulka [17.4K]3 years ago
7 0

Answer:

Solution given:

Centre(h,k)=(-5,-9)

radius (r)=7

we have

Equation of a circle is;

(x-h)²+(y-k)²=r²

Substituting value;

(x+5)²+(y+9)²=7²

<u>(x+5)²+(y-9)²=49 is a required equation of a circle</u>.

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Find the minimum value of <br> C=x+3y
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Answer:

DNE

Step-by-step explanation:

If x and y may be any real number, there is no minimum value for C. It can approach negative infinity.

If C is a constant, and the domain of x is all real numbers, there is no minimum for y. It can approach negative infinity.

We're not sure what you want or what restrictions may exist. The given relation does not suggest any minimum. We'd have to say it Does Not Exist

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The projected value (in millions of dollars) of a large manufacturing company is modeled by the function V(t) - 230(1.12)', wher
Natali5045456 [20]

Answer:

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we know that

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V(t)=a(1+r)^t

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a is the initial value or y-intercept

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a=230\\1+r=1.12\\r=1.12-1\\r=0.12\\r=12\%

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Remember that

t is the number of years since 2018

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230 is the  value of the company in 2018

3 0
3 years ago
TRIGONOMETRY - Given the complex numbers <img src="https://tex.z-dn.net/?f=z_%7B1%7D%20%3D20%20cis%20226" id="TexFormula1" title
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This is easily done after writing both complex numbers in exponential form:

z_1=20\,\mathrm{cis}226^\circ=20e^{226^\circ i}

z_2=5\,\mathrm{cis}76^\circ=5e^{76^\circ i}

Then

\dfrac{z_1}{z_2}=\dfrac{20e^{226^\circ i}}{5e^{76^\circ i}}=4e^{(226-76)^\circ i}=4e^{150^\circ i}

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8 0
3 years ago
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